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<span>Point B has coordinates (3,-4) and lies on the circle. Draw the perpendiculars from point B to the x-axis and y-axis. Denote the points of intersection with x-axis A and with y-axis C. Consider the right triangle ABO (O is the origin), by tha conditions data: AB=4 and AO=3, then by Pythagorean theorem:
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{Note, that BO is a radius of circle and it wasn't necessarily to use Pythagorean theorem to find BO}
<span>The sine of the angle BOA is</span>

Since point B is placed in the IV quadrant, the sine of the angle that is <span> drawn in a standard position with its terminal ray will be </span>
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6 = -2b (cancel -2b on both sides)
6/-2 = b (divide both sides by -2)
-3 = b (simplify 6/2 to 3)
now switch sides
Answer: b = -3
Answer:

Step-by-step explanation:
<u>Formula:</u> 




Well the math you would do is 3346/7. That equals 478. As a fraction in simplest form you could write 478/1