Answer:
The most expensive she can buy is the soccerball
Step-by-step explanation:
Given






Required
Using
, what is the most expensive she can buy?

Subtract $15.32 from both sides



This means that she can not afford items that cost more than $13.68
i.e. the shin guards which costs $14.98
The items she can afford and their prices are:



The most expensive of them all is:

A quadratic with roots at 8 and 5 is f(x) = x^2 + 10x - 24
In order to find an equation given roots you can create statements that equal 0 in order to create parenthesis. For instance we know x = 8 at one point. So, we can solve that to equal 0.
x = -12 ----> add 8 from both sides
x + 12 = 0
We can do the same for the other zero.
x = 2 ----> subtract from both sides
x - 2 = 0
Now that we have both of these, we can multiply these two things together. This will give us the function we need.
f(x) = (x + 12)(x - 2)
f(x) = x^2 + 12x - 2x - 24
f(x) = x^2 + 10x - 24
Answer:
4 5/6 feet.
Step-by-step explanation:
The least common multiple for 2 and 3 is 6, so if we change the denominators to 6, we get Chrystelle's height as 3 3/6, and her mother is 1 4/6 ft taller than her.
3 3/6 + 1 4/6= ?
(Written as an Improper fraction)
21/6 + 10/6 = 31/6
31/6 = 4 5/6.
I hope this helps!
Answer:
The Possible dimension of the ring could be;
20 ft × 60 ft
25 ft × 48 ft
30 ft × 40 ft
60 ft × 20 ft
48 ft × 25 ft
40 ft × 30 ft
Step-by-step explanation:
Given:
Number of skaters = 30
Area for each skater = 40 sq ft
We need to find the dimension of rectangular ring the are going to build.
Now we know that they building the skating ring such that they all can use at same time.
Hence if the all use at same time then we will find the total area first.
Total area can be calculated by multiplying Number of skaters with area required for each skaters.
Framing the equation we get;
Total area = 
Hence The total area of the rectangular ring would be 1200 sq. ft.
Now we know that Total area is equal to product of length and width.

1200 can be written as = 20 × 60, 25 × 48, 30 × 40,60 × 20,48 × 25,40 × 30
Hence the Possible dimension of the ring could be;
20 ft × 60 ft
25 ft × 48 ft
30 ft × 40 ft
60 ft × 20 ft
48 ft × 25 ft
40 ft × 30 ft