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3 years ago

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Pinciotto's lego company has $3.2*10(to the power of 8) to give out in bonus money to their employees. If there are 42000 employ

ees approximately how much will each employee receive. Write in standard form. Round to the nearest hundredth.

1 answer:

Rainbow [258]3 years ago

6 0

Answer:

7619.04

In scientific notation, it's 7.62 * 10^3

Step-by-step explanation:

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Whoch expression is equivalent to -20 - (-4)

dangina [55]

Answer:

D

Step-by-step explanation:

-(-4)=+4

so it is -20+4

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3 years ago

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(x2 - y2)-(-x2 + y2)<br> How do you write that out to show work ?! Help pleAse

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do it or he will hunt you down and kill u (lets destroy the moderators!!!!!!!!)

we are slowing them down already! good work soilders!

Step-by-step explanation:

8 0

3 years ago

What is the value of X?

LenKa [72]

Answer:

5.625 or 5-5/8 or 45/8

Step-by-step explanation:

Solve using Similar triangles again

ratio of 4:7.5

3/x=4/7.5 cross multiply

22.5=4x

x=22.5/4=5.625=5-5/8=45/8

7 0

3 years ago

Pzz look at this problem first person with correct answer will get branliest

galina1969 [7]

Answer:

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Step-by-step explanation:

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3 years ago

Set up the integral that represents the arc length of the curve f(x) = ln(x) + 5 on [1, 3], and then use Simpson's Rule with n =

marta [7]

Answer:

The integral for the arc of length is:

$\displaystyle\int_1^3\sqrt{1+\frac{1}{x^2}}dx$

By using Simpon’s rule we get: 1.5355453

And using technology we get: 2.3020

The approximation is about 33% smaller than the exact result.

Explanation:

The formula for the length of arc of the function f(x) in the interval [a,b] is:

$\displaystyle\int_a^b \sqrt{1+[f'(x)]^2}dx$

We need the derivative of the function:

$f'(x)=\frac{1}{x}$

And we need it squared:

$[f'(x)]^2=\frac{1}{x^2}$

Then the integral is:

$\displaystyle\int_1^3\sqrt{1+\frac{1}{x^2}}dx$

Now, the Simposn’s rule with n=4 is:

$\displaystyle\int_a^b g(x)}dx\approx\frac{\Delta x}{3}\left( g(a)+4g(a+\Delta x)+2g(a+2\Delta x) +4g(a+3\Delta x)+g(b) \right)$

In this problem:

$a=1,b=3,n=4, \displaystyle\Delta x=\frac{b-a}{n}=\frac{2}{4}=\frac{1}{2},g(x)= \sqrt{1+\frac{1}{x^2}}$

So, the Simposn’s rule formula becomes:

$\displaystyle\int_1^3\sqrt{1+\frac{1}{x^2}}dx\\\approx \frac{\frac{1}{3}}{3}\left( \sqrt{1+\frac{1}{1^2}} +4\sqrt{1+\frac{1}{\left(1+\frac{1}{2}\right)^2}} +2\sqrt{1+\frac{1}{\left(1+\frac{2}{2}\right)^2}} +4\sqrt{1+\frac{1}{\left(1+\frac{3}{2}\right)^2}} +\sqrt{1+\frac{1}{3^2}} \right)$

Then simplifying a bit:

$\displaystyle\int_1^3\sqrt{1+\frac{1}{x^2}}dx \approx \frac{1}{9}\left( \sqrt{1+\frac{1}{1^2}} +4\sqrt{1+\frac{1}{\left(\frac{3}{2}\right)^2}} +2\sqrt{1+\frac{1}{\left(2\right)^2}} +4\sqrt{1+\frac{1}{\left(\frac{5}{2}\right)^2}} +\sqrt{1+\frac{1}{3^2}} \right)$

Then we just do those computations and we finally get the approximation via Simposn's rule:

$\displaystyle\int_1^3\sqrt{1+\frac{1}{x^2}}dx\approx 1.5355453$

While when we do the integral by using technology we get: 2.3020.

The approximation with Simpon’s rule is close but about 33% smaller:

$\displaystyle\frac{2.3020-1.5355453}{2.3020}\cdot100\%\approx 33\%$

8 0

3 years ago