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expeople1 [14]
3 years ago
7

Write a program that accepts an integer value called multiplier as user input. Create an array of integers with ARRAY_SIZE eleme

nts. This constant has been declared for you in main, and you should leave it in main. Set each array element to the value i*multiplier, where i is the element's index. Next create two functions, called PrintForward() and PrintBackward(), that each accept two parameters: (a) the array to print, (b) the size of the array. The PrintForward() function should print each integer in the array, beginning with index 0. The PrintBackward() function should print the array in reverse order, beginning with the last element in the array and concluding with the element at index 0. (Hint: for help passing an array as a function parameter, see zybooks section 6.23) As output, print the array once forward and once backward.
Computers and Technology
1 answer:
Tasya [4]3 years ago
6 0

Answer:

The program in C++ is as follows:

#include <iostream>

using namespace std;

void PrintForward(int myarray[], int size){

   for(int i = 0; i<size;i++){        cout<<myarray[i]<<" ";    }

}

void PrintBackward(int myarray[], int size){

   for(int i = size-1; i>=0;i--){        cout<<myarray[i]<<" ";    }

}

int main(){

   const int ARRAY_SIZE = 12;

   int multiplier;

   cout<<"Multiplier: ";

   cin>>multiplier;

   int myarray [ARRAY_SIZE];

   for(int i = 0; i<ARRAY_SIZE;i++){        myarray[i] = i * multiplier;    }

   PrintForward(myarray,ARRAY_SIZE);

   PrintBackward(myarray,ARRAY_SIZE);

   return 0;}

Explanation:

The PrintForward function begins here

void PrintForward(int myarray[], int size){

This iterates through the array in ascending order and print each array element

<em>    for(int i = 0; i<size;i++){        cout<<myarray[i]<<" ";    }</em>

}

The PrintBackward function begins here

void PrintBackward(int myarray[], int size){

This iterates through the array in descending order and print each array element

<em>    for(int i = size-1; i>=0;i--){        cout<<myarray[i]<<" ";    }</em>

}

The main begins here

int main(){

This declares and initializes the array size

   const int ARRAY_SIZE = 12;

This declares the multiplier as an integer

   int multiplier;

This gets input for the multiplier

   cout<<"Multiplier: ";    cin>>multiplier;

This declares the array

   int myarray [ARRAY_SIZE];

This iterates through the array and populate the array by i * multiplier

<em>    for(int i = 0; i<ARRAY_SIZE;i++){        myarray[i] = i * multiplier;    }</em>

This calls the PrintForward method

   PrintForward(myarray,ARRAY_SIZE);

This calls the PrintBackward method

   PrintBackward(myarray,ARRAY_SIZE);

   return 0;}

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Write a program that takes in an integer in the range 20-98 as input. The output is a countdown starting from the integer, and s
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Answer:

// program in C++.

#include <bits/stdc++.h>

using namespace std;

int main() {

//  variable  

int num;

cout<<"Enter the number between 20 and 98: ";

// read number

cin >> num;

while(num<20||num>98)

{

   cout<<"Wrong input!!enter number between 20-98 only:";

   cin>>num;

}

cout<<"The output is: ";

while(num % 10 != num /10)

{

// print numbers.  

cout<<num<<" ";

// update num.

num--;

}

// display the number.

cout<<num<<endl;;

return 0;

}

Explanation:

Read a number from user and assign it to variable "num".Check if entered number  is in between 20-98 or not.If input number is less than 20 or greater than 98 then  ask again to enter a number between 20-98 until user enter a valid input.Then print  the countdown from input number till both the digit of number are same.

Output:

Enter the number between 20 and 98: 99                                                                                    

Wrong input!!enter number between 20-98 only:12                                                                            

Wrong input!!enter number between 20-98 only:93                                                                            

The output is: 93 92 91 90 89 88

Enter the number between 20 and 98: 77                                                                                    

The output is: 77

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