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Sever21 [200]
3 years ago
6

The number 63 is how many times the number 21?

Mathematics
2 answers:
Andrei [34K]3 years ago
8 0

Answer:

21 * 3 = 63

Step-by-step explanation:

tatiyna3 years ago
3 0

Answer:

3

Step-by-step explanation:

cause 63 divided by 21 is 3.

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I think the second one hope this helps
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3 years ago
What is the quadratic function that is created with roots at 2 and 4 and a vertex at (3, 1)?
Arada [10]
Hello,

y=k*(x-2)(x-4)
and is passing throught (3,1)
==>1=k*(3-2)(3-4)==>k=-1

y=-(x-2)(x-4) is an answer
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Same amount as 2 hundreds + 14 tens +3 ones<br><br><br><br> please help
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3 years ago
Find the distance between the points (3, –8) and (0, –9).
nadezda [96]

The formula for distance between two points is:

\sqrt{(x_{2} -x_{1})^{2} + (y_{2} -y_{1})^{2}}

In this case:

x_{2} =0\\x_{1} =3\\y_{2} =-9\\y_{1} =-8

^^^Plug these numbers into the formula for distance like so...

\sqrt{(0-3)^{2} + (-9 - (-8))^{2}}

To solve this you must use the rules of PEMDAS (Parentheses, Exponent, Multiplication, Division, Addition, Subtraction)

First we have parentheses. Remember that when solving you must go from left to right

\sqrt{(0-3)^{2} + (-9-(-8))^{2}}

0 - 3 = -3

\sqrt{(-3)^{2} + (-9-(-8))^{2}}

-9 - (-8) = -1

\sqrt{(-3)^{2} + (-1)^{2}}

Next solve the exponent. Again, you must do this from left to right

\sqrt{(-3)^{2} + (-1)^{2}}

(-3)² = 9

\sqrt{9 + (-1)^{2}}

(-1)² = 1

\sqrt{(9+1)}

Now for the addition

\sqrt{(9+1)}

9 + 1 = 10

√10 <<<This can not be further simplified so this is your exact answer

Your approximate answer would be about 3.16

***Remember that the above answers are in terms of units

Hope this helped!

~Just a girl in love with Shawn Mendes

4 0
3 years ago
Can u please answer?
lorasvet [3.4K]

Answer:

35 cm²

Step-by-step explanation:

A=bl

so

A=5(7) so

A=

35 cm²

5 0
3 years ago
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