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Zepler [3.9K]
3 years ago
11

Joanne cannot decide which of two washing machines to buy. The selling price of each is ​$720. The first is marked down by 50​%.

The second is marked down by ​30% with an additional ​% off. Find the sale price of each washing machine. Use pencil and paper. Explain why should buy the first washing machine rather than the second if the machines are the same except for the selling price.
Mathematics
1 answer:
Archy [21]3 years ago
4 0

Answer:

More expensive

Step-by-step explanation:

FIRST WASHING MACHINE PRICE - $360

SECOND WASHING MACHINE PRICE - MUST NOT BE CHEAPER

$720 x 30% = $216

The additional percentage must make the washing machine more expensive than the first one.  

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Jeff dog weighs 76 pounds. what is the dog's weight rounded to the nearest ten pounds?
Leno4ka [110]
The dog would be an estimate of 80 pounds.
6 0
3 years ago
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If a couple were planning to have three​ children, the sample space summarizing the gender outcomes would​ be: bbb,​ bbg, bgb,​
marusya05 [52]

Answer:

(a) The sample space is: S = {bb, bg, gb, gg}

(b) The probability that the couple has two girl children is 0.25.

(c) The probability that the couple has exactly 1 boy and 1 girl child is 0.50.

Step-by-step explanation:

A boy child is denoted by, <em>b</em>.

A girl child is denoted by, <em>g</em>.

(a)

A couple has two children.

The sample space for the possible gender of the two children are:

The couple can have two boys, two girls or 1 boy and 1 girl.

So the sample space is:

S = {bb, bg, gb, gg}

(b)

It is provided that the outcomes of the sample space <em>S</em> are equally likely, i.e. each outcome has the same probability of success.

Compute the probability that the couple has two girl children as follows:

P (2 Girls) = Favorable no. of outcomes ÷ Total no. of outcomes

                =\frac{1}{4} \\=0.25

Thus, the probability that the couple has two girl children is 0.25.

(c)

Compute the probability that the couple has exactly 1 boy and 1 girl child as follows:

P (1 boy & 1 girl) = Favorable no. of outcomes ÷ Total no. of outcomes

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Thus, the probability that the couple has exactly 1 boy and 1 girl child is 0.50.

7 0
3 years ago
If you’re good with probability math 30 please help with questions 33 and 35! real answers only
drek231 [11]

Answer:  33) b      34) a        35) none

<u>Step-by-step explanation:</u>

33)

Filling in the Venn Diagram (from Left to right, including outside of circles):

T only           = 13

(T ∩ F)only   =  6

F only           = 21

(T ∩ D) only  =  3

T ∩ F ∩ D     =  5

(F ∩ D) only  =  8

D only           = 15

<u>(T ∪ F ∪ D)'    = 11   </u>

   TOTAL      = 82

P(D'\cap F) = \dfrac{6+21}{13+6+21+3+5+8+15+11}\quad =\large\boxed{\dfrac{27}{82}}

34)

Red  = 26

Face  = 12

Red ∩ Face = 6

Total cards = 52

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<em>I think the teacher made an error, if so, then the answer is "d".</em>

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<span>12/15 sds </span>


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