4 packs of notepads and 5 packs of sticky notes
Explanation: if he needs the same number of both he needs to find the first number that 4 and 5 both go into. 4 x 5 = 20 so this is the least common multiple

8 0

3 years ago

Read 2 more answers

Find the variable of z; 3 4.5 1.5 z

serg [7]

Answer: 1.5..?

Step-by-step explanation:

6 0

3 years ago

Solve for x. 3x−1=9x+2 Enter your answer in the box. x =

julia-pushkina [17]

Answer:

x= -1

Step-by-step explanation:

3x-1=2x2 (calculate the product)

3x-1=4x (move terms)

3 x - 4 x =1 (collect the terms)

- x = 1 (change the signs)

Solution is x = -1

3 0

3 years ago

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4 employees drive to work in the same car. the workers claim they were late to work because of a flat tire. their managers ask t

Brums [2.3K]

Answer:

The required probability is 0.015625.

Step-by-step explanation:

Consider the provided information.

There number of tires are 4.

The number of workers are 4.

The probability that individual select front drivers side tire = $\frac{1}{4}$

The probability that they all select front drivers side,tire is: $\frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}=\frac{1}{256}$

Similarly,

The probability that they all select front passenger side, tire is: $\frac{1}{256}$

The probability that they all select rear driver side,tire is: $\frac{1}{256}$

The probability that they all select rear passenger side, tire is: $\frac{1}{256}$

Hence, the probability that all four workers select the same tire = $\frac{1}{256}+ \frac{1}{256}+\frac{1}{256}+\frac{1}{256}$

the probability that all four workers select the same tire = $\frac{4}{256}=\frac{1}{64}=0.015625$

Hence, the required probability is 0.015625.

5 0

3 years ago

You average weekly pay for the past six weeks is $140. What do you need to earn on the seventh week for the average to be $145?​

You average weekly pay for the past six weeks is $140. What do you need to earn on the seventh week for the average to be $145?