You can factoring problems using fhe GCF
1) if ∠J=∠E and ∠G=∠A ⇒ ΔCJG ~ Δ<span>CEA
2) </span>if ∠J=∠E and JC:JC=JG:EA ⇒ ΔCJG ~ Δ<span>CEA
3) </span>if JC:JC=JG:EA= CG:CA ⇒ ΔCJG ~ Δ<span>CEA</span>
If it means what method used then say two step equations
-2a from both sides leaving you with 7a-7=14 then add 7 to both side leaving you with 7a=21 then a=3 i hope it helps if not then lmk
Answer:
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Step-by-step explanation:
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