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LuckyWell [14K]
3 years ago
7

Choose the type of literary device being used in the example below.

English
1 answer:
Vinil7 [7]3 years ago
3 0

Answer: metaphor

This is a comparison between two things that doesn’t use “like” or “as”, so it is a metaphor.

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He was as strong as an ox.
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It would be a simile because a simile is a comparison using "like" or "as"
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Read the excerpt from The Dark Game: True Spy Stories from Invisible Ink to CIA Moles.
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Read the excerpt from The Dark Game: True Spy Stories from Invisible Ink to CIA Moles.

<em>[T]he Germans committed some blunders in the way they sent their secret radio messages, giving the British help in their task. The first mistake of German intelligence was the error of arrogance, believing that the British were not up to the challenge of deciphering their messages. Another mistake they made was sending duplicates and even triplicates of some of their messages, with each one using a different cipher key.</em>

Question: Which word best describes the tone of the passage?    

Options:

  • Critical
  • Apologetic
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  • Discouraged

Answer: The correct answer is: <u>Critical.</u>

Explanation: A critical tone is used to express an analysis of merits and faults of something or someone. The passage talks about The German's secret radio messages against the British. It expresses adverse and disapproving comments towards the Germans, by mentioning that The German intelligence was arrogant and that they committed terrible mistakes in the way they sent their secret radio messages.

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3 years ago
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46. Philosophers are not sure _____________ .
Anni [7]

Answer:

Can is not in the right place. A is incorrect because of Placement and the it just doesn't make much sense. That's why C is the answer.

Explanation:

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2 years ago
What do great teams use to their advantage?
34kurt
They used their ability to focus & work together
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3 years ago
Please solve with explanation
kondaur [170]

Answer:

Following are the responses to the given point:

Explanation:

r=8\ cm\\\\h=10 \ cm\\\\l=\sqrt{r^2+h^2}=\sqrt{10^2+8^2}=\sqrt{100+64}=\sqrt{164}

Area of cone:

A=\pi r l +\pi r^2\\\\

   =\pi\times 8\times \sqrt{164} +\pi \times 8^2\\\\=\frac{22}{7}\times 8(\sqrt{164} + 8)\\\\= 522.92\ cm^2\\\\=522.9 \ cm^2\\

Volume of cone:

v=\frac{1}{3}\pi r^2 h\\\\

  =\frac{1}{3} \times\frac{22}{7} \times 8^2 \times 10\\\\=670.2\ cm^3\\\\

Calculating the empty space:

V' =\text{cylinder volume- cone volume}= \pi r^2h-\frac{1}{3} \pi r^2h=\frac{2}{3} \pi r^2h\\\\

V'=2 \times \text{cone volume} \\\\

    =2 \times 670.2\ cm^2\\\\=1340.4\ cm^2

3 0
2 years ago
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