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tatuchka [14]
3 years ago
10

True or False?

Mathematics
2 answers:
Blizzard [7]3 years ago
7 0

Answer:True

Step-by-step explanation: I did a quiz on it

Bess [88]3 years ago
5 0

Answer:

it is true am I right of this question

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If 9a+6b+4c=7, what is -24b-16c-36a
Alexandra [31]

Answer:

-24b - 16c - 36a = -28

Step-by-step explanation:

Given the initial equation of 9a + 6b + 4c = 7 and looking at the second equation of -24b - 16c - 36a, I notice that all of the coefficients of the variables have been multiplied by a factor of -4.  Since all of the factors have been multiplied by the same factor, multiplied the answer to the equation by a -4 as well will give us the answer to the problem.  Since the original answer is 7, multiplying this answer by a factor of -4:  (7)(-4) = -28.  

3 0
3 years ago
What is the exact area of a circle whose radius is 9 yd? Enter your answer in the box. Express your answer in terms of
atroni [7]

Answer:

81\pi

Step-by-step explanation:

Area = pi*r^2

Area = pi*9^2

Area = 81\pi

6 0
3 years ago
Read 2 more answers
Which of the following is a polynomial with roots 4, 2i, and −2i?
alexira [117]
If the roots are r1,r2,r3, the facotred polynomail looksl ike this
f(x)=(x-r1)(x-r2)(x-r3)

given
roots 4,2i and -2i

f(x)=(x-4)(x-2i)(x-(-2i))
f(x)=(x-4)(x-2i)(x+2i)
expand
f(x)=x³-4x²+4x-16
3rd option
5 0
3 years ago
Lisa drove to the mountains last weekend. There was heavy traffic on the way there, and the trip took 12 hours. When Lisa drove
Liono4ka [1.6K]
Well if we times twenty miles with eight hours the answer is 160 miles
7 0
4 years ago
Expanding logarithmic Expression In Exercise,Use the properties of logarithms to rewrite the expression as a sum,difference,or m
wel

Answer:

\frac{1}{2}ln(2x)-\frac{1}{2}ln(x^2-1)

Step-by-step explanation:

In 2x/(x^2 - 1)1/2

ln(\frac{2x}{x^2-1} )^\frac{1}{2}

Apply the property of natural log

ln x^m = m ln(x) move the exponent before ln

ln(\frac{2x}{x^2-1} )^\frac{1}{2}

\frac{1}{2}ln(\frac{2x}{x^2-1})

ln(m/n)= ln m - ln n

\frac{1}{2}(ln(2x)-ln(x^2-1))

multiply 1/2 inside the terms

\frac{1}{2}ln(2x)-\frac{1}{2}ln(x^2-1)

6 0
3 years ago
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