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Yuki888 [10]
3 years ago
13

What is the domain and the range of the relation represented by the ordered pairs?

Mathematics
1 answer:
castortr0y [4]3 years ago
6 0
The correct answers are #1 and #4
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What is the area of the composite figure? ___ units^2
elena-14-01-66 [18.8K]

Answer:

  34 square units

Step-by-step explanation:

The figure can be considered to be a trapezoid with a rectangle removed.

The area of the trapezoid is ...

  A = (1/2)(b1 +b2)h

  A = (1/2)(10 +6)(5) = 40

The area of the rectangle is ...

  A = LW

  A = (3)(2) = 6

Then the area of the shaded portion of the figure is ...

  shaded area = trapezoid area - rectangle area

  = 40 - 6 = 34 . . . square units

7 0
3 years ago
A machine stamps 330 parts in 11 minutes. Find the unit rate in parts per hour.
zavuch27 [327]

Answer:

1,800 parts per hour

Step-by-step explanation:

330 parts = 11 min

330/11=30

30 parts = 1 min

60 min = 1 hour

30x60min=1,800

1,800 parts per hour

5 0
3 years ago
Rite the fraction in order from greatest to least 2/8 5/8 1/8
Elanso [62]
I'm guessing it is 5/8 than 2/8 and last 1/8 it HAS to be what i just said
4 0
3 years ago
Read 2 more answers
Martin had M dollars initially. First, Martin spent 1/3 of his money. Then Martin spent 3/4 of what was left. Finally, Martin sp
Ilya [14]

Answer:

first he had M some unknown amount 

then he had 2/3 M since he spent 1/3 M

then he spent 3/4 of the (2/3 M) so he had 1/4 of the ( 2/3M) 

then he spent what was left $20 so $20 = 1/4 ( 2/3 M) now solve for M

and check by doing each step and figuring how much was spent and how much left.

<u>another</u><u> </u><u>method</u><u> </u>

let us consider the left amount be Y and total now of M dollar be X

then

Y = amount of money Nartin has left 

Y = X - ( 1/3 ) ( X ) - ( 3/4 ) ( X - 1/3 X ) - 20 

Y = X - 1/3 X - 3/4 X + 3/12 X - 20 

Y = X - 4/12 X - 9/12 X + 3/12 X - 20 

Y = X - 10/12 X - 20 

Y = X - 5/6 X - 20 

Y = ( 1 / 6 ) ( X ) - 20 

<u>hope</u><u> </u><u>it</u><u> </u><u>helped</u><u> </u><u>u</u><u> </u><u>buddy</u><u> </u><u /><u>:</u><u> </u><u>)</u>

5 0
3 years ago
If 6m by 15m is a pond ,is 40m would be enough for fencing the pond
Veseljchak [2.6K]
If the pond were a rectangle, then:
length=15 m
width=6 m

We would have to calculate the perimeter of this rectangle.
Perimeter of a rectangle=2(length)+2(width)

Perimeter of this rectangle=2(15 m)+2(6 m)=30 m+12 m=42 m

We need 42 m and I only have 40 m, therefore, it would not be enough for fencing the pond. 
4 0
3 years ago
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