Answer:
We cannot say that the mean wake time are different before and after the treatment, with 98% certainty. So the zopiclone doesn't appear to be effective.
Step-by-step explanation:
The goal of this analysis is to determine if the mean wake time before the treatment is statistically significant. The question informed us the mean wake time before and after the treatment, the number of subjects and the standard deviation of the sample after treatment. So using the formula, we can calculate the confidence interval as following:
![IC[\mu ; 98\%] = \overline{y} \pm t_{0.99,n-1}\sqrt{\frac{Var(y)}{n}}](https://tex.z-dn.net/?f=IC%5B%5Cmu%20%3B%2098%5C%25%5D%20%3D%20%5Coverline%7By%7D%20%5Cpm%20t_%7B0.99%2Cn-1%7D%5Csqrt%7B%5Cfrac%7BVar%28y%29%7D%7Bn%7D%7D)
Knowing that 
:
![IC[\mu ; 98\%] = 98.9 \pm 2.602\frac{42.3}{4} \Rightarrow 98.9 \pm 27.516](https://tex.z-dn.net/?f=IC%5B%5Cmu%20%3B%2098%5C%25%5D%20%3D%2098.9%20%5Cpm%202.602%5Cfrac%7B42.3%7D%7B4%7D%20%5CRightarrow%2098.9%20%5Cpm%2027.516)
![IC[\mu ; 98\%] = [71.387 ; 126,416]](https://tex.z-dn.net/?f=IC%5B%5Cmu%20%3B%2098%5C%25%5D%20%3D%20%5B71.387%20%3B%20126%2C416%5D)
Note that ![102.8 \in [71.384 ; 126.416]](https://tex.z-dn.net/?f=102.8%20%5Cin%20%5B71.384%20%3B%20126.416%5D)
so we cannot say, with 98% confidence, that the mean wake time before treatment is different than the mean wake time after treatment. So the zopiclone doesn't appear to be effective.
The coordinates of Ship A and B are missing, so i have attached it
Answer:
The vessel in distress is located at the coordinate (1, 2)
Step-by-step explanation:
The coordinates attached shows that;
Coordinates of A are (3, 4) while that of B are (1, 1).
We are told that Ship A receives a distress signal from the north, And ship B receives a distress signal from the same vessel from the southeast.
Now, from the image attached, If we imagine extending the line of ship A that is getting distress signal from southeast and also same thing for ship B that is getting signal from north,we'll discover that the lines intersect at a point with co-ordinates of approximately; (1, 2)
If A and B are equal:
Matrix A must be a diagonal matrix: FALSE.
We only know that A and B are equal, so they can both be non-diagonal matrices. Here's a counterexample:
![A=B=\left[\begin{array}{cc}1&2\\4&5\\7&8\end{array}\right]](https://tex.z-dn.net/?f=A%3DB%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D1%262%5C%5C4%265%5C%5C7%268%5Cend%7Barray%7D%5Cright%5D)
Both matrices must be square: FALSE.
We only know that A and B are equal, so they can both be non-square matrices. The previous counterexample still works
Both matrices must be the same size: TRUE
If A and B are equal, they are literally the same matrix. So, in particular, they also share the size.
For any value of i, j; aij = bij: TRUE
Assuming that there was a small typo in the question, this is also true: two matrices are equal if the correspondent entries are the same.
Negative x positive = negative
Negative x negative = positive
-4 x 8 = -32
-4 x -1 = 4
-4 x -5 = 20
-4 x 9 = -36
Answer: |-32 4 20 -36|
Allison can make 4 fruit parfaits.
Since one parfait requires 1/8 cup of yogurt, add:
1/8 + 1/8 + 1/8 + 1/8
They all share a common denominator, so:
1/8 + 1/8 +1/8 + 1/8 = 4/8
Simplify your answer (divide numerator and denominator by the common factor of 2) :
4/8 = 1/2
1/2 represents the total amount of cups of yogurt used. Since it took adding 1/8 four times that represents 4 parfaits.
