Answer:
The mean of the distribution of heights of students at a local school is 63 inches and the standard deviation is 4 inches.
Step-by-step explanation:
The normal curve approximating the distribution of the heights of 1000 students at a local school is shown below.
For a normal curve, the mean, median and mode are the same and represents the center of the distribution.
The center of the normal curve below is at the height 63 inches.
Thus, the mean of the distribution of heights of students at a local school is 63 inches.
The standard deviation represents the spread or dispersion of the data.
From the normal curve it can be seen that values are equally distributed, i.e. the difference between two values is of 4 inches.
So, the standard deviation is 4 inches.
Answer:
a). The company's percentage=60%
b). The total premium=$812.50
c). The company's payment=$487.50
Step-by-step explanation:
a).
The total premium can be expressed as;
T=H+R
where;
T=proportion of total premium
H=proportion paid by Harold Wagner
R=remaining proportion
In our case;
T=100%
H=40%
R=r
replacing;
100%=40%+r
r=100%-40%
r=60%
The company's percentage=60%
b).
The total premium, if 40%=$325.00
Let total premium be=t
40% of t=325
(40/100)×t=325
0.4 t=325
t=325/0.4
t=$812.50
The total premium=$812.50
c).
The company's payment=60% of total premium
The company's payment=(60/100)×812.5
The company's payment=$487.50
Number of pounds purchased multiplied by price per pound equals the total $ spent.
x= # pumpkin pounds purchased
0.49x=$73.50
Divide both sides by 0.49
x=150 pumpkin pounds purchased
Hope this helps! :)
The number with the least value is 2.62
