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shepuryov [24]
3 years ago
7

please answer right ill give brainliest don't submit a wrong answer if u just want the points comment and ill help u get a lot m

ore points just don't submit a wrong answer pleasee

Mathematics
2 answers:
masya89 [10]3 years ago
7 0
Y=x squared if i’m correct
disa [49]3 years ago
5 0

Answer:

Y=x(squared)

Step-by-step explanation:

Use this equation to get x and y from the table

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F(x) = x2 – 2x - 8
maw [93]

Answer:

The y-intercept is the point (0,-8)

see the attached figure

Step-by-step explanation:

we have

f(x)=x^{2}-2x-8

we know that

The y-intercept is the value of the function f(x) when the value of x is equal to zero

so

For x=0

f(x)=0^{2}-2(0)-8\\f(x)=-8

therefore

The y-intercept is the point (0,-8)

see the attached figure to better understand the problem

5 0
3 years ago
When Ms. Lawrence goes to the doctor’s office, they have patients wait 30 minutes. She found a new doctor that has 15% less wait
baherus [9]

Answer:

25.5 minutes

Step-by-step explanation:

3 0
3 years ago
What is the cube root of 27a^l2?<br>-3a4<br>-3a<br> 3a<br> 3a*​
GuDViN [60]

Answer:

3a^4

Step-by-step explanation:

What is the cube root of  27a^{12}? This is the question.

We can write:

\sqrt[3]{27a^{12}}

We will use the below property to simplify:

\sqrt[n]{a*b}=\sqrt[n]{a}  \sqrt[n]{b}

So, we have:

\sqrt[3]{27a^{12}} =\sqrt[3]{27} \sqrt[3]{a^{12}}

We will now use below property to further simplify:

\sqrt[n]{x} =x^{\frac{1}{n}}

Thus, we have:

\sqrt[3]{27} \sqrt[3]{a^{12}} =3*(a^{12})^{\frac{1}{3}}

We know power to the power rule:  (a^z)^b=a^{zb}

Now, we have:

3*(a^{12})^{\frac{1}{3}}\\=3*a^{\frac{12}{3}}\\=3a^4

This is the correct answer:  3a^4

4 0
3 years ago
Can someone please help me on these questions!!!
34kurt

Answer:

#1 is 28

Step-by-step explanation:

Set the perimeters equal, as 6x - 2 = 8x - 12, solve for x = 5, and plug in.

3 0
3 years ago
Find the exact value of x
Ket [755]
<span>What does lol, idk, and ttyl mean? I am serious Answer me and I will answer you
:D please

</span>
3 0
3 years ago
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