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3 years ago

Can someone help me with this math homework please!

Mathematics

2 answers:

Troyanec [42]3 years ago

7 0

Here's your answer.

1.(-1,0)

2.(0,2)

Vlad1618 [11]3 years ago

5 0

Answer:

$x-intercept=(-1,0)$

$y-intercept=(0,2)$

Hope it helps...

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Please help!!!!! will give brainliest!!! thank you so so so much, I really appreciate it

Dmitriy789 [7]

Answer:

Step-by-step explanation:

Firstly, we will identify the angle that has the given cosine value

From what we can see, the arc cos of this value is 45 degrees

but, as we can see, the value is negative

On the quadrants, the value of cosine is negative on the 2nd and 3rd quadrant

2nd quadrant ranges from 90 - 180

That is pi/2 to pi

3rd ranges from 180 to 270

That is pi to 3pi/2

Kindly recall, we are considering angles from -360 to 360

So what this mean is that we will consider angles that are negative of what we have as positive angles on the first and fourth quadrant on which cosine is positive

Thus, we have the following;

5pi/4 is same as 225 degrees

This is on the 3rd quadrant, and cosine is negative there

7pi/4 is same as 315 and this is on the fourth quadrant

This is expected to be negative because normally, cosine is positive on that axis and what we have should be negative

3pi/4 is same as 135

This is on the second quadrant and normally, cosine is negative here so we do not need to negate the angle measure

pi/4 is on the first quadrant and cosine is positive here;

Since the value we have here is positive, we have to negate the angle measure

So the correct angles are;

negative pi/4

positive 3pi/4

positive 5pi/4

negative 7pi/4

6 0

3 years ago

An unfair coin has probability 0.3 of landing heads. The coin is tossed seven times. What is the probability that it lands heads

solmaris [256]

Answer:

0.9176 = 91.76% probability that it lands heads at least once

Step-by-step explanation:

For each time that the coin is tossed, there are only two possible outcomes. Either it lands heads, or it does not. The probability of a toss landing heads is independent of other tosses. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$