So basically
D=RT
distance=rate times time
D=233
carlos speed=55
maria speed=50
total time=4.4 hours
so therefor we have to represent
carlos time
maria time
carlos distance
maria dstance
let's say that
remember that whatever carlost drove is 233 minus maria (time and distance)
and since we are solving for maria time and distnace, solve in terms of them
maria time=t
maria distance=d
carlos time=4.4-t
carlos distance=233-d
remember total D=RT
find their seperate equations
carlos
233-d=55(4.4-t)
maria
d=50(t)
use them to solve
233-d=55(4.4-t)
subsitute 50(t) for d
233-50t=55(4.4-t)
add 50t to both sides
233=55(4.4-t)+50t
distribute using distributiver protperty (a(b+c)=ab+ac)
55(4.4-t)=242-55t
233=242-55t+50t
add like terms
233=242-5t
add 5t to both sides
233+5t=242
subtract 233 from both sides
5t=9
divdie both sides by 5
t=1.8
maria drove 1.8 hours
the answer is A
Answer:
A) 0.05
Step-by-step explanation:
Let's summarize into an equation the information we can get from that table.
We have 4 liters of an acid of an unknown concentration, let's call it (4x).
We have 10 liters of an acid with known concentration of 0.40.
And we have a total of 14 liters overall with a concentration of 0.3o.
That's like a weighted average formula: 4x + 10 y = 14z
Let's replace the concentration values we know and solve this:
4x + 10 (0.4) = 14 * 0.3
4x + 4 = 4.2
4x = 0.2
x = 0.05
So, the concentration of the 4 liters of acid on concentration X are in fact of concentration of 0.05.
If I’m not mistaken, the answer should be C.
Let me know if I was correct.
The sixth graders collected $250 of their $300 goal. The seventh graders collected $250 of thier $450 goal.
Sixth Graders:
$250 / $300
Reduce: $25 / $30 = 5/6
Seventh Graders:
$250 / $450
Reduce: $25 / $45 = 5/9
Answer is (A) because it is concave and it has 8 sides
