All categories

3 years ago

Why is it important to reread your e-mails before you send them?

English

2 answers:

Digiron [165]3 years ago

8 0

It's very important to re-read your emails before sending them out for a couple of reasons:

1. You need to make sure you're sending it to the correct person(s).

2. Proof reading will make sure that you spot any grammatical errors or spelling errors to make sure you don't look foolish; especially if it's an important topic.

svetlana [45]3 years ago

5 0

To proof read, make sure you didn't do any mistakes

You might be interested in

I used to be so much more helpful and be better, I miss the times where i was better and less dumb and and even less confidence

harkovskaia [24]

Answer:

yes

Explanation:

ytrwFASJYHRTAD SGFDZNBmgf HGSADMnhf

3 0

3 years ago

The author MOST LIKELY included a picture with this article to show A) why the news is important. B) why people enjoy newspapers

leva [86]

Answer: How the printing presses worked.

Explanation:

7 0

3 years ago

Read 2 more answers

I will make you brainlist if you help me the 2 question by explain them i swear i will make you brainlist

Xelga [282]

★ Formula Applied :

$\begin{gathered}\sf \bullet\ \; cos^2x-sin^2x=cos2x\\\\\to\ \sf \pink{sin^2x-cos^2x=-cos2x}\end{gathered}$

$\begin{gathered}\bullet\ \; \sf sin2x=2.sinx.cosx\\\\\to \sf \blue{sinx.cosx=\dfrac{sin2x}{2}}\end{gathered}$

$\displaystyle \bullet\ \; \sf \int \dfrac{dx}{x}$

$\bullet\ \; \sf \ln (ab)=\ln a+\ln$

★ Explanation :

$\begin{gathered}\displaystyle \sf \int \dfrac{sin^2x-cos^2x}{sinx.cosx}dx\\\\\to \sf \int \dfrac{-cos2x}{\frac{sin2x}{2}}dx\\\\\to \sf \int \dfrac{-2cos2x}{sin2x}dx\end{gathered}$

Lets use substitution method ,

Let , u = sin2x

⇒ du = 2.cos2x.dx

$\begin{gathered}\to \displaystyle \sf \int \dfrac{-du}{u}\\\\\to \sf -\int \dfrac{du}{u}\\\\\to \sf -ln|u|\\\\\end{gathered}$

$\to \sf \red{-ln|sin2x|+c}$

$\to \sf - \ln |2sinx.cosx|+c$

$\to \sf - \ln |sinx.cosx|+(\ln 2+c)$

$\leadsto - \sf \red{\ln |sinx.cosx|+c}\ \; \bigstar$

★ Alternate Method :

$\displaystyle \sf \int \dfrac{sin^2x-cos^2x}{sinx.cosx}$

$\displaystyle \to \sf \int \left( \dfrac{sin^2x}{sinx.cosx}-\dfrac{cos^2x}{sinx.cosx}\right)dx$

$\begin{gathered}\displaystyle \to \sf \int \left( \dfrac{sinx}{cosx} -\dfrac{cosx}{sinx} \right)dx\\\\\to\ \sf \int (tanx-cotx)dx\\\\\to \sf \int tanx.dx-\int cotx.dx\\\\\to \sf ln|secx|-ln|sinx|+c\end{gathered}$