okay well usually what I would tell you would be to use the ABC method. you would multiply A (2) by C (6) to get twelve. so you need two numbers that multiply to twelve and add to -4 (the B value). but there are no numbers that fit this description so you have to use the GCF method instead
for this method you must find the GCF for all three numbers which in this case is 2. 2(x^2-2x+3) all these numbers are now prime so this is the factored form
Answer:
y=11
x=-4
Step-by-step explanation:
y =-x+7
2x-5y=-7
insert the first equation into the second like so...
2x+5x-35=-7
Now rearrange...
2x+5x=-7+35
Now solve...
7x=-28
x=-4
Now incert x in any equation...
y=4+7
y=11
x = 13
subtract x from both sides of the equation
6 = 2x - x - 7
6 = x - 7
add 7 to both sides
6 + 7 = x ⇒ x = 13
As a check
substitute this value into the equation and if both sides are equal then it is the solution
left side = 13 + 6 = 19
right side = (2 × 13) - 7 = 26 - 7 = 19
hence x = 13 is the solution
