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Andreyy89
3 years ago
7

PLEASE HELP

Mathematics
1 answer:
Mkey [24]3 years ago
8 0

Answer:

1) 3,6,9

2) the pattern will keep growing around 3 multiple

3) the next pattern is 12,15

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The scores on the entrance exam at a well-known, exclusive law school are normally distributed with a mean score of 200 and a st
ruslelena [56]

Answer:

the lowest passing score would be x = 298

Step-by-step explanation:

School wishes that only 2.5 percent of students taking test pass

We are given

mean= 200,

standard deviation = 50

We need to find x

The area under the curve can be found by:

2.5 % = 0.025

So, 1- 0.025 = 0.975

We need to find the value of z for which the answer is 0.975

Looking at the z-score table, the value of z is: 1.96

Now, using the formula:

z = x - mean/standard deviation

1.96 = x - 200/50

=> 1.96 * 50 = x-200

98 = x - 200

=> x = 200+98

x = 298

So, the lowest passing score would be x = 298

8 0
3 years ago
Please help giving 50 points and brainlyest if correct
zmey [24]

Answer:

1.f 2.a 3.j 4.e

Step-by-step explanation:

you add and subtract the needed like terms

for example you can add 3x with 4x but not with 4x² because it's a different degree

3 0
3 years ago
Read 2 more answers
jordan go's to the bank every 7 days and then Clare go's to the bank every day will bolth go to the bank
RUDIKE [14]

Answer:

on the seventh day

Step-by-step explanation:

hope this helps

8 0
3 years ago
A rectangular garden has a walkway around it. The area of the garden is 4​(6.5x+3.5​). The combined area of the garden and the w
alexdok [17]

Answer:The area of the walkway around is 26 x + 16 as the sum of two terms

Step-by-step explanation:

3 0
3 years ago
if you deposit $500 at an interest rate of 3% for four years, how much will you receive when you withdraw it from the bank?
Ray Of Light [21]
 1st year 500* 0.03 = 15+500=515
 2nd year 515*0.03=  15.45 + 515 = 530.45
 3rd year 530.45*0.03= 15.9135 + 530.45 = 546.3635
 4th year 546.3635 * 0.03 = 16.390905 + 546.3635 = 562.754405
562.754405
8 0
3 years ago
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