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Ksenya-84 [330]
3 years ago
8

If george drives at a steady rate of 65 miles per hour, how many miles will he travel in 1.5 hours

Mathematics
1 answer:
Oxana [17]3 years ago
7 0
He will travel the distance of 97.5 miles
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Help me wit dis pleasee??
elixir [45]
A straight line is 180 degrees. To get x, you subtract 117 from 180.

180-117 is 63.

x= 63.

x+y is 90 degrees so to find y, you subtract x from 90.

90-63 is 26.

y=27.
4 0
3 years ago
The cost (in dollars) of making b bracelets is represented by 4 5b. The cost (in dollars) of making b necklaces is represented b
Leviafan [203]

Answer:

$(3b+2)

Step-by-step explanation:

The cost of making b bracelets = 4+5b

The cost  of making b necklaces = 8b+6.

To determine how much more it cost to make b necklaces than b bracelets, we simply subtract.

Extra Cost = Cost of b Necklaces-Cost of b Bracelets

=(8b+6)-(4+5b)

open the brackets

=8b+6-4-5b

Collect like terms

=8b-5b+6-4

=3b+2

It costs $(3b+2) more to make b necklaces than b bracelets.

3 0
3 years ago
During a sale , a shop allows 20%
Dafna1 [17]

Answer:

$24

Step-by-step explanation:

original price of a dress = $30

discount = 20%

discount amount = discount% of original price

=20/100 * 30

=30/5

=$6

price that consumer will pay after discount = $30 - $6

=$24

6 0
3 years ago
Read 2 more answers
Assume f is a one to one function of f(x)= 4-6x find f^-1(-32)​
OleMash [197]

Answer:

f^-1(-32)=6

Step-by-step explanation:

<u>Find the inverse of the function f(x)=4-6x:</u>

f(x)=4-6x

y=4-6x

x=4-6y

x-4=-6y

(x-4)/-6=y

-1/6x+2/3=y

y=-1/6x+2/3

f^-1(x)=-1/6x+2/3

<u>Plug in f^-1(-32) for f^-1(x) and simplify:</u>

f^-1(-32)=-1/6(-32)+2/3

f^-1(-32)=16/3+2/3

f^-1(-32)=18/3

f^-1(-32)=6

5 0
2 years ago
What is the true solution to the equation below? 2 In e^In2x -In e^In10x = In 30
stealth61 [152]

The\ domain.\\D:x\in\mathbb{R^+}\\\\2\ln e^{\ln2x}-\ln e^{\ln10x}=\ln30\ \ \ |use\ \log_ab^n=n\log_ab\\\\2\ln2x\ln e-\ln10x\ln e=\ln30\ \ \ \ |use\ \log_aa=1\\\\2\ln2x-\ln10x=\ln30\ \ \ |use\ n\log_ab^n=\log_ab^n\\\\\ln(2x)^2-\ln10x=\ln30\\\\\ln4x^2-\ln10x=\ln30\ \ \ |use\ \log_ab-\log_ac=\log_a\dfrac{b}{c}\\\\\ln\dfrac{4x^2}{10x}=\ln30\\\\\ln\dfrac{2x}{5}=\ln30\iff\dfrac{2x}{5}=30\ \ \ \ |\cdot5\\\\2x=150\ \ \ \ |:2\\\\x=75\in D

Answer: x = 75

8 0
3 years ago
Read 2 more answers
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