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Dima020 [189]
3 years ago
14

Solve the equation 14 + 14p = 21 for p. A. 1/2 B. 1/3 C. 1/6 D. 1/8

Mathematics
1 answer:
hram777 [196]3 years ago
5 0
It’s 1/2 or A because
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Answer:

Step-by-step explanation:

3x - 7y + 12 = 5x - 9

-7y = 5x - 3x - 9 - 12

-7y = 2x - 21

7y = 2x + 21

y = 2/7x + 3

3 0
3 years ago
An ellipse has a co-vertex at (–8, 9) and a foci at (4, 4). If the center of the ellipse is located below the given co-vertex, t
vovikov84 [41]

Answer:

Step-by-step explanation:

“the center of the ellipse is located below the given co-vertex”

Co-vertex and center are vertically aligned, so the ellipse is horizontal.

Equation for horizontal ellipse:

(x-h)²/a² + (y-k)²/b² = 1

with

a² ≥ b²

center (h,k)

vertices (h±a, k)

co-vertices (h, k±b)

foci (h±c,k), c² = a² -b²

One co-vertex is (-8,9), so h = -8.

One focus is (4,4), so k = 4.

Center (h,k) = (-8,4)

c = distance between center and focus = |-8 - 4| = 12

b = |9-k| = 5

a² = c² + b² = 169

(x+8)²/169 + (y-4)²/25 = 1

7 0
3 years ago
Find the area of the shape​
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3 0
3 years ago
In what quadrant does the angle 2pi/3 terminate? I II III IV
dem82 [27]

Answer:

The angle 2pi/3 terminate in quadrant II

Step-by-step explanation:

Quadrant I ⇒ 0 < θ < (π/2)

Quadrant II ⇒ (π/2) < θ < (π)

Quadrant III ⇒ (π) < θ < (3π/2)

Quadrant IV⇒ (3π/2) < θ < (2π)

When θ = 2π/3

∴ (π/2) < θ < (π)

So, The angle 2pi/3 terminate in quadrant II

4 0
4 years ago
Read 2 more answers
Plz help !!!!!!!!!!!!!!!!!!!!!!
NNADVOKAT [17]

Answer:

Step-by-step explanation:

x^2 + 7x + 5x + 35

7x : II

5x: III

35: IV

7 0
3 years ago
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