Answer:
Step-by-step explanation:
3x - 7y + 12 = 5x - 9
-7y = 5x - 3x - 9 - 12
-7y = 2x - 21
7y = 2x + 21
y = 2/7x + 3
Answer:
Step-by-step explanation:
“the center of the ellipse is located below the given co-vertex”
Co-vertex and center are vertically aligned, so the ellipse is horizontal.
Equation for horizontal ellipse:
(x-h)²/a² + (y-k)²/b² = 1
with
a² ≥ b²
center (h,k)
vertices (h±a, k)
co-vertices (h, k±b)
foci (h±c,k), c² = a² -b²
One co-vertex is (-8,9), so h = -8.
One focus is (4,4), so k = 4.
Center (h,k) = (-8,4)
c = distance between center and focus = |-8 - 4| = 12
b = |9-k| = 5
a² = c² + b² = 169
(x+8)²/169 + (y-4)²/25 = 1
what shape is this? and yes i can change the answer so its not this hellooooooooooooooo whats the shape?
bro whats the shape
I CANNOT ANSWER THE QUESTION WITHOUT KNOWING THE SHAPE
Answer:
The angle 2pi/3 terminate in quadrant II
Step-by-step explanation:
Quadrant I ⇒ 0 < θ < (π/2)
Quadrant II ⇒ (π/2) < θ < (π)
Quadrant III ⇒ (π) < θ < (3π/2)
Quadrant IV⇒ (3π/2) < θ < (2π)
When θ = 2π/3
∴ (π/2) < θ < (π)
So, The angle 2pi/3 terminate in quadrant II
Answer:
Step-by-step explanation:
x^2 + 7x + 5x + 35
7x : II
5x: III
35: IV
