PLEASE I NEED HELP !!!!!!

3.3 find the length of the side indicated. And round to 1 decimal place

patriot [66]

Answer:

31.1

Step-by-step explanation:

This is an isosceles triangle. Let us name the unnamed side y. y will also equal 22. We also know that this is a right triangle so using the pythagorean theorem we can calculate x. x = √(22^2+22^2) so x = 31.1.

5 0

2 years ago

find the area of the trapezium whose parallel sides are 25 cm and 13 cm The Other sides of a Trapezium are 15 cm and 15 CM

Snezhnost [94]

$\huge\underline{\red{A}\blue{n}\pink{s}\purple{w}\orange{e}\green{r} -}$

Given - A trapezium ABCD with non parallel sides of measure 15 cm each ! along , the parallel sides are of measure 13 cm and 25 cm

To find - Area of trapezium

Refer the figure attached ~

In the given figure ,

AB = 25 cm

BC = AD = 15 cm

CD = 13 cm

Construction -

$draw \: CE \: \parallel \: AD \: \\ and \: CD \: \perp \: AE$

Now , we can clearly see that AECD is a parallelogram !

$\therefore$ AE = CD = 13 cm

Now ,

$AB = AE + BE \\\implies \: BE =AB - AE \\ \implies \: BE = 25 - 13 \\ \implies \: BE = 12 \: cm$

Now , In ∆ BCE ,

$semi \: perimeter \: (s) = \frac{15 + 15 + 12}{2} \\ \\ \implies \: s = \frac{42}{2} = 21 \: cm$

Now , by Heron's formula

$area \: of \: \triangle \: BCE = \sqrt{s(s - a)(s - b)(s - c)} \\ \implies \sqrt{21(21 - 15)(21 - 15)(21 - 12)} \\ \implies \: 21 \times 6 \times 6 \times 9 \\ \implies \: 12 \sqrt{21} \: cm {}^{2}$

Also ,

$area \: of \: \triangle \: = \frac{1}{2} \times base \times height \\ \\\implies 18 \sqrt{21} = \: \frac{1}{\cancel2} \times \cancel12 \times height \\ \\ \implies \: 18 \sqrt{21} = 6 \times height \\ \\ \implies \: height = \frac{\cancel{18} \sqrt{21} }{ \cancel 6} \\ \\ \implies \: height = 3 \sqrt{21} \: cm {}^{2}$

Since we've obtained the height now , we can easily find out the area of trapezium !

$Area \: of \: trapezium = \frac{1}{2} \times(sum \: of \:parallel \: sides) \times height \\ \\ \implies \: \frac{1}{2} \times (25 + 13) \times 3 \sqrt{21} \\ \\ \implies \: \frac{1}{\cancel2} \times \cancel{38 }\times 3 \sqrt{21} \\ \\ \implies \: 19 \times 3 \sqrt{21} \: cm {}^{2} \\ \\ \implies \: 57 \sqrt{21} \: cm {}^{2}$

hope helpful :D

6 0

1 year ago

I NEED HELP ASAP

Allushta [10]

Euler's formula is given by:
C + V = A + 2
Where,
C: number of faces
V: number of vertices
A: number of edges.
Clearing A we have:
A = C + V-2
Substituting values:
A = 21 + 14-2
A = 33
Answer:
the missing number is:
C.33

7 0

3 years ago

Divide the whole into pieces that are each ⅙ of the whole. Then, solve the equation.

yKpoI14uk [10]

Answer: 6

Explanation

If we divide our figure into six, we get the following figure:

As we can see, we are left with 6 equal parts. This can be confirmed by solving the equation:

$1\div\frac{1}{6}=\frac{6}{1}=6$

6 0

1 year ago

Can a Scalene triangle be a isosceles triangle? A: Always B: Never C: Sometimes

arsen [322]

A scalene triangle can never be an isosceles triangle. How? Well, let's take a look at the definition of a scalene triangle. In short, a scalene triangle is a classification of a triangle that does not have any congruent sides. On the other hand, an isosceles triangle is a triangle in which its legs are both congruent. Therefore, if a scalene triangle has two congruent legs, it wouldn't even be a scalene triangle, but instead it would be an isosceles triangle. Hope this helped!

3 0

3 years ago