Answer:

Step-by-step explanation:
*Missing Part of the Question*
4 stars
5 triangles
3 circles
3 squares
Required
Determine the probability of triangle being first then square being second


Represent the triangle with T and square with S
So, we're solving for P(T n S)

Solving for P(T)


Solving for P(S)
The question implies a probability without replacement;
Hence Total has now been reduced by 1
Total = 14


Recall that




Hence, the required probability is

Answer:
Yes it is true and 4 mark not ture
Step-by-step explanation:
Length =l
Height = h
Area function = l * h = 924
Perimeter function = 2i + 2h = 122
Divide by 2
I + h = 61.
Plug in I or h for the other variable
I * (61 - I) = 924
61i - i^2 = 924
Factor the function
(-I + 28)(I - 33) = 0
l = 33 as l cannot be negative
61 - 33 = 28
h = 28
Difference between h and l is 33-28=5