Area of the whole sector = 1/2 r^2 theta ( theta in radians)
= 1/2 * 18.6^2 * 123 * pi/180 = 371.35 m^2
Area of the triangle = 1/2 r^2 sin theta = 1/2 * 18.6^2 * sin 123 = 145.07 m^2
Area of shaded segment = 371.35 - 145.07 = 229.3 m^2 to nearest tenth
Answer:
23.08 < µ < 36.9
Step-by-step explanation:
First we need to find the sample mean and standard deviation.
Sample mean: Add up the values and divide by the total amount of values...
(26.2 + 17.8 + 23.1 + 36.0 + 31.1 + 43.2 + 36.4 + 26.1)/8 = 239.9/8 = 29.99
The sample standard deviation is calculated on the first attached photo
s = 8.27
The confidence interval is constructed in the second attached photo
You first draw two circles when different radii.
When you select two point over the circumference, and you connect a line in between these points and the center of the circle, you will always obtain two sides with the same length. It is because the length of these sides coincides witht the ratio of the circle.
Then, when you connect the points over the circumference between them, you have a side that can have a different length compared with the lengths of the lines connected to the center. Thus, you obtain an isosceles triangle; you have two sides with the same length (remember, it's the same as the radius) and one side with another length.
Answer:
The area is 9 unit squared
Step-by-step explanation:
Given
The right parameters are:
Required
The area of the triangle
This is calculated as:
So, we have:
<em>Hence, the area is 9 unit squared</em>
Hi there!
From the diagram, we can see that ΔAEF, and ΔACB are similar, isosceles triangles.
Therefore:
∠B and ∠F are congruent because they are corresponding angles, and ∠B and ∠E are congruent because of equal base angles in an isosceles triangle.
Therefore:
7x - 11 = 6x
Subtract 6x from both sides:
x - 11 = 0
Add 11 to both sides:
x = 11.