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ozzi
3 years ago
8

The function Y = sin3x/cos3x function, and the function y = 1/sec3x is function

Mathematics
1 answer:
Viefleur [7K]3 years ago
8 0
1/34
step-by-step-explanation
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Write and equation for the trend line shown
Zepler [3.9K]

Answer:

y = -\frac{10}{3}<em>x</em> + 70

or

y = 70 -\frac{10}{3}x

(They're both the same equation, whichever one you prefer you can use!)

7 0
3 years ago
Find the slope of the line Someone please help me!!
d1i1m1o1n [39]
-1/4
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rises 1
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8 0
4 years ago
If the null space of A4×5 is exactly a two-dimensional plane, answer the following:
Hatshy [7]

Answer:

I.

A is a 4 x 5 matrix => A: U -> V, dim U = 5, dim V = 4

Null space is exactly two dimensional plane

dim null (A) = 2

II.

Rank A = dim U - dim Null A = 5 - 2 = 3

III.

Number of linearly Independent columns of A is the rank of A = 3

IV.

Yes, The system Ax = b has no solution sometimes as range of A \neq V

V.

Yes,Sometimes Ax = b has a unique solution

VI.

Yes, sometimes Ax = b has infinitely many solutions

8 0
3 years ago
Customers arrive at a service facility according to a Poisson process of rate λ customers/hour. Let X(t) be the number of custom
mash [69]

Answer:

Step-by-step explanation:

Given that:

X(t) = be the number of customers that have arrived up to time t.

W_1,W_2... = the successive arrival times of the customers.

(a)

Then; we can Determine the conditional mean E[W1|X(t)=2] as follows;

E(W_!|X(t)=2) = \int\limits^t_0 {X} ( \dfrac{d}{dx}P(X(s) \geq 1 |X(t) =2))

= 1- P (X(s) \leq 0|X(t) = 2) \\ \\ = 1 - \dfrac{P(X(s) \leq 0 , X(t) =2) }{P(X(t) =2)}

=  1 - \dfrac{P(X(s) \leq 0 , 1 \leq X(t)) - X(s) \leq 5 ) }{P(X(t) = 2)}

=  1 - \dfrac{P(X(s) \leq 0 ,P((3 \eq X(t)) - X(s) \leq 5 ) }{P(X(t) = 2)}

Now P(X(s) \leq 0) = P(X(s) = 0)

(b)  We can Determine the conditional mean E[W3|X(t)=5] as follows;

E(W_1|X(t) =2 ) = \int\limits^t_0 X (\dfrac{d}{dx}P(X(s) \geq 3 |X(t) =5 )) \\ \\  = 1- P (X(s) \leq 2 | X (t) = 5 )  \\ \\ = 1 - \dfrac{P (X(s) \leq 2, X(t) = 5 }{P(X(t) = 5)} \\ \\ = 1 - \dfrac{P (X(s) \LEQ 2, 3 (t) - X(s) \leq 5 )}{P(X(t) = 2)}

Now; P (X(s) \leq 2 ) = P(X(s) = 0 ) + P(X(s) = 1) + P(X(s) = 2)

(c) Determine the conditional probability density function for W2, given that X(t)=5.

So ; the conditional probability density function of W_2 given that  X(t)=5 is:

f_{W_2|X(t)=5}}= (W_2|X(t) = 5) \\ \\ =\dfrac{d}{ds}P(W_2 \leq s | X(t) =5 )  \\ \\  = \dfrac{d}{ds}P(X(s) \geq 2 | X(t) = 5)

7 0
4 years ago
Giving the 2 sides of the triangle, find the range of all possible lengths for the third side.
Zinaida [17]

Answer:

  1. 2 < x < 16
  2. 3 < x < 19
  3. 14 < x < 18
  4. 4 < x < 16
  5. 13 < x < 47
  6. 0 < x < 10
  7. 1 < x < 7

Step-by-step explanation:

The minimum third side is the difference of the given sides; the maximum third side is their sum.

If you like, you can have a spreadsheet calculate these for you. That seems like more work than just doing them in your head.

4 0
3 years ago
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