Answer:
V = 603.19 unit^3
or
V = 192π unit^3
Step-by-step explanation:
V = πr^2 *h
V = π(8)^2 *3
<u>V = 603.19 unit^3</u>
or
<u>V = 192π unit^3</u>
Complete question is;
The terminal side of angle θ in standard position, intersects the unit circle at P(-10/26, -24/26). What is the value of csc θ?
Answer:
csc θ = -13/12
Step-by-step explanation:
We know that in a unit circle;
(x, y) = (cos θ, sin θ)
Since the the terminal sides intersects P at the coordinates P(-10/26, -24/26), we can say that;
cos θ = -10/26
sin θ = -24/26
Now we want to find csc θ.
From trigonometric ratios, csc θ = 1/sin θ
Thus;
csc θ = 1/(-24/26)
csc θ = -26/24
csc θ = -13/12
Answer:
Step-by-step explanation:
S = 2WL + 2LH + 2WH
S - 2WH = 2WL + 2LH
S - 2WH = L(2W + 2H)
(S - 2WH) / (2W + 2H) = L <===
Answer:
c I think but I am not sure but I hope you have a good day
The answer is B) x is equal to all real numbers.
The domain of a function is the numbers for x that you can put in. Although the y-values are restricted here, you can put any number you want in for x. Therefore, x is equal to all real numbers.
