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3 years ago

Which expression is equivalent to the expression 6h + 2?

Mathematics

2 answers:

Degger [83]3 years ago

7 0

I think the second answer is correct

evablogger [386]3 years ago

4 0

Answer:

Step-by-step explanation:

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Solve x2 – 8x = 3 by completing the square. Which is the solution set of the equation?

vazorg [7]

Answer:

x = 4 ± $\sqrt{19}$

Step-by-step explanation:

Given

x² - 8x = 3

To complete the square

add ( half the coefficient of the x- term )² to both sides

x² + 2(- 4)x + 16 = 3 + 16

(x - 4)² = 19 ( take the square root of both sides )

x - 4 = ± $\sqrt{19}$ ( add 4 to both sides )

x = 4 ± $\sqrt{19}$

8 0

3 years ago

Read 2 more answers

Estimate the difference. 9 1/2- 1 6/7

Sav [38]

Answer:

$= 7 \frac{9}{14} \\$

Step-by-step explanation:

$9 \frac{1}{2} - 1 \frac{6}{7} \\ \frac{19}{2} - \frac{13}{7} \\ \frac{133 - 26}{14} \\ = \frac{107}{14} \\ = 7 \frac{9}{14}$

hope this helps

brainliest appreciated

good luck! have a nice day!

6 0

4 years ago

A right triangle has a hypotenuse of 153 centimeters and a leg of 72 centimeters. What is the length of the other leg?

Luba_88 [7]

81 cent.........................................................

7 0

3 years ago

Analyze the diagram below and complete the instructions that follow.

lora16 [44]

Answer:

$\displaystyle y=2\sqrt{6}$

$\displaystyle x=2\sqrt{2}$

Step-by-step explanation:

<u>Trigonometric Ratios </u>

The ratios of the sides of a right triangle are called trigonometric ratios.

The longest side of the right triangle is called the hypotenuse and the other two sides are the legs.

Selecting any of the acute angles as a reference, it has an adjacent side and an opposite side. The trigonometric ratios are defined upon those sides.

The image provided shows a right triangle whose hypotenuse is given. We are required to find the value of both legs.

Let's pick the angle of 30°. Its adjacent side is y. We can use the cosine ration, which is defined as follows:

$\displaystyle \cos 30^\circ=\frac{\text{adjacent leg}}{\text{hypotenuse}}$

$\displaystyle \cos 30^\circ=\frac{y}{4\sqrt{2}}$

Solving for y:

$y=4\sqrt{2}\cos 30^\circ$

Since:

$\cos 30^\circ=\frac{\sqrt{3}}{2}$

$\displaystyle y=4\sqrt{2}\frac{\sqrt{3}}{2}$

Simplifying:

$\displaystyle y=2\sqrt{6}$

Now we use the sine ratio:

$\displaystyle \sin 30^\circ=\frac{\text{opposite leg}}{\text{hypotenuse}}$

$\displaystyle \sin 30^\circ=\frac{x}{4\sqrt{2}}$

Solving for x:

$x=4\sqrt{2}\sin 30^\circ$

Since:

$\sin 30^\circ=\frac{1}{2}:$

$\displaystyle x=4\sqrt{2}\frac{1}{2}$

Simplifying:

$\displaystyle x=2\sqrt{2}$

The choices are not clear, but it seems like the correct answer is C.

$\boxed{\displaystyle y=2\sqrt{6}}$

$\boxed{\displaystyle x=2\sqrt{2}}$

6 0

3 years ago

Find the slope of the line through the given points.<br> (-3,-18) and (1,2)

katovenus [111]

Answer:

Step-by-step explanation:

Slope (m) =

ΔY

ΔX

= 5

θ =

arctan( ΔY )

ΔX

= 78.69006752598°

ΔX = 1 – -3 = 4

ΔY = 2 – -18 = 20

Distance (d) = √ΔX2 + ΔY2 = √416 = 20.396078054371

Equation of the line:

y = 5x – 3

When x=0, y = -3

When y=0, x = 0.6

7 0

3 years ago