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Lady_Fox [76]
3 years ago
10

Write a recursive formula for a_na n ​ , the n^{\text{th}}n th term of the sequence 16, -8, 4, ...16,−8,4,....

Mathematics
1 answer:
julia-pushkina [17]3 years ago
3 0

Answer:

aₙ = -2aₙ₊₁

Step-by-step explanation:

According to the sequence given 16, -8, 4, ...

a1 = 16

a2 = -8

a3 = 4

From the values, we can conclude thst;

a1 = -2(-8)

Since a2 = -8, then;

a1 = -2(a2)

Similarly

a2 = -2(4)

a2 = -2a3

The subsequent sequence are;

a3 = -2a4

The nth term will ne;

aₙ = -2aₙ₊₁

Hence the required recursive function is aₙ = -2aₙ₊₁

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What is the product of 187 x 70?
Semenov [28]
ANSWER: 13090

EXPLANATION: okay so basically whenever you see the word "product" it means that you just have to multiply. So their asking what is 187 x 70 and well, it's 13090
hopefully this helps you in the future!! :D
6 0
3 years ago
6+6y=-30 solve for y​
kakasveta [241]

Answer:

y = -6

Step-by-step explanation:

6 + 6y = -30

6y = -30 - 6

6y = -36

y = -6

7 0
3 years ago
A student can do an average of 25 math problems an hour. If at a certain time of day, he has done 40 math problems, how many pro
yanalaym [24]

Answer:

90

Step-by-step explanation:

now: 40

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after two hours: 65+25 = 90

7 0
3 years ago
What is the correct step to solve for the variable? 15 = m - 5
Mandarinka [93]

Answer:

Add 5 to the left side.

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5 0
3 years ago
Read 2 more answers
A DNA sequence can be represented as a string of the letters ACTG (short for adenine, cytosine, guanine, and thymine). How many
maria [59]

To solve that question we can think by the following way:

  • The first letter can be any of the letters (A, C, T or G). Therefore there are 4 possibilites.
  • To choose the second letter of the sequence, any letter also can be chose. So, one more time, there are 4 possibilites.

Using the fundamental principle of counting, we will find out that can be formed 4\times 4 = 16 differents sequences (for example, AA, AG, TT, TG, CT...).

Know we know that, we can generalize. If I have n elements and I must choose one of them t times to do a sequence, the total number of sequence that I can form will be n^t.

In our question, we want to know how many DNA sequence are exactly 29 letters long. As indicated above, the answer for that is 4\times 4\times 4\times ... \times 4 (29 times) = 4^{29}.

Therefore, there are 4^{29} DNA sequences with exactly 29 letters long.

I hope I've helped you. =D

Enjoy your studies. \o/

8 0
3 years ago
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