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Lisa [10]
3 years ago
9

Which statement about copper, diamond, and silicon(IV) dioxide is correcta)Copper and silicon(IV) dioxide have similar electrica

l conductivityb)In diamond the carbon atoms are covalently bonded as flat sheetsc)In silicon(IV)dioxide the silicon and oxygen atoms are covalently bonded in flat sheetsd)The structure of copper includes a lattice of positive ions
Chemistry
1 answer:
kondor19780726 [428]3 years ago
3 0

Answer:

In diamond the carbon atoms are covalently bonded as flat sheets

In silicon(IV) dioxide the silicon and oxygen atoms are covalently bonded in flat sheets

The structure of copper includes a lattice of positive ions

Explanation:

Diamond and silicon(IV) dioxide are covalent network solids. Covalent network solids are made up of atoms joined to one another by covalent bonds to form a giant lattice, The solids are hard and have a very high melting point. They do not conduct electricity. So, for both diamond and SiO2, atoms are covalently bonded to yield flat sheets in a covalent bonded network solid.

Copper is a metallic substance having metallic bonds, a metallic crystal consists of positive ions and a cloud of electrons.

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