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Ainat [17]
2 years ago
13

The volume of a rectangular box is 1600 cubic inches. The height of the box is 8 inches and the length of the box is 2 times lon

ger than the width of the box. What is the width of the box "IN FEET FT"?
Mathematics
1 answer:
Anastasy [175]2 years ago
7 0

Answer:

0.833 feets

Step-by-step explanation:

Given that:

Volume of box = 1600

Heigh of box (H) = 8 inches

Let:

Width of box (W) = x

Length of box (L) = 2x

Volume of box = (Height * width * length)

1600 = (8 * x * 2x)

1600 = 16x²

x² = 1600/16

x² = 100

x = sqrt(100)

x = 10 inches

Hence, width of box in feet:

1 inch = 0.0833 feets

10 inches = (10 * 0.0833) feets

= 0.833 feets

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The sides of two cubes are in the ratio 2:1. What is the ratio of their volumes ?
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Answer:

we know that, Volume of cube=a³

Let volume of 1st cube be 2x with side a and other be x with side A (according to given ratio)

Step-by-step explanation:

ATQ: 2x=a³ and, x=A³

a=³√2x and, A=x

we know that, surface area of cube is 6a²

Thus, surface area of 1st cube = 6(³√2x)²

= 6³√4x²

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5 0
2 years ago
Three friends each have some ribbon. Carl has 54 inches of ribbon,Tino has 13.5 feet of ribbon, and Baxter has 3.5 yards of ribb
deff fn [24]

Answer:

  342 inches, or 28.5 feet, or 9.5 yards

Step-by-step explanation:

It is perhaps easiest to start with all the dimensions in inches.

  13.5 ft = (13.5 ft)(12 in/ft) = 162 in

  3.5 yd = (3.5 yd)(36 in/yd) = 126 in

Then the total of the lengths of ribbon is ...

  54 in + 162 in + 126 in = 342 in

Converting to feet, we get ...

  (342 in)/(12 in/ft) = 28.5 ft

And converting to yards, we get ...

  (342 in)/(36 in/yd) = 9.5 yd

The total length of ribbon is 342 inches, or 28.5 feet, or 9.5 yards.

7 0
3 years ago
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What is the area of the figure below​
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Answer:

Option A

Step-by-step explanation:

Area of the composite figure = Area of ΔABH + Area of BCGH + Area of ΔDEF

Area of ΔABH = \frac{1}{2}(\text{Base})(\text{Height})

                        = \frac{1}{2}(6)(8-5)

                        = 9 in²

Area of the trapezoid = \frac{1}{2}(CG+BH)(\text{Distance between these lines})

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2 years ago
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