So it is asking you to group like term so
x terms can be grouped/added/subtracted to other x terms, but not to x^2 or x^3 terms
x^2 terms to x^2 and so on so
1. 9-3k+5k=
9+(5k-3k)=
9+2k
2. k^2+2k+4k=
k^2+(2k+4k)=
k^2+6k=
and 
. So we have a remainder of
and 
. Subtracting this from the previous remainder gives a new remainder
and 
. Subtracting this from the previous remainder gives a new one of
and we're done since 2 does not divide 
. So we have
Answer:
Step-by-step explanation:
We know that the length is four times the width, so:
We also know the area, which is 324 m². The formula for area:
Insert the known values:
Solve for w. Simplify by removing parentheses:
Divide 4 from both sides to isolate the variable:
Find the square root of both sides:
The width is 9 m.
We know the width. Now find the length by using the area formula and inserting known values:
Solve for l. Divide both sides by 9:
The length of the rectangle is 36. (You can check: 4 times 9 is 36)
Now find the perimeter:
Insert values:
The perimeter is 90 m.
Yes you can! Say you have 5(2 + x) + 3x. The answer would be 10+8x because when you use the distributive property you will end up getting 5*2 5*x and once you multiply, it's obvious 5 times 2 is 10 and 5 times x will equal 5x. Then you add 5x and 3x and get 8x. So, the simplified expression here is 10+8x. When you have this as an answer it's proving your answer right. You can without using the distributive property. We can have 10+5x+3x and it will be your simplified expression. It's the same thing with equations too.
Answer:
Step-by-step explanation:
Is there a question somewhere in there?
