PLEASE HELP ASAP PLEASE AND THANK YOU

Un bloc de la ville de New York a été représenté dans une grille. Chaque case contient un immeuble de

Andreas93 [3]

Step-by-step explanation:

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4 0

3 years ago

The graph 4x^2-4x-1 is shown. Use the grpah to find the estimates for the solutions of 4x^2-4x-1=0 and 4x^2 - 4x-1=2

Darina [25.2K]

Answer:

a) The estimates for the solutions of $4\cdot x^{2}-4\cdot x -1 = 0$ are $x_{1}\approx -0.25$ and $x_{2} \approx 1.25$ .

b) The estimates for the solutions of $4\cdot x^{2}-4\cdot x -1 = 2$ are $x_{1}\approx -0.5$ and $x_{2} \approx 1.5$

Step-by-step explanation:

From image we get a graphical representation of the second-order polynomial $y = 4\cdot x^{2}-4\cdot x -1$ , where $x$ is related to the horizontal axis of the Cartesian plane, whereas $y$ is related to the vertical axis of this plane. Now we proceed to estimate the solutions for each case:

a) $4\cdot x^{2}-4\cdot x -1 = 0$

There are two approximate solutions according to the graph, which are marked by red circles in the image attached below:

$x_{1}\approx -0.25$ , $x_{2} \approx 1.25$

b) $4\cdot x^{2}-4\cdot x -1 = 2$

There are two approximate solutions according to the graph, which are marked by red circles in the image attached below:

$x_{1}\approx -0.5$ , $x_{2} \approx 1.5$

5 0

3 years ago

How to calculate monthly salary 5,000 month salary?

Vlada [557]

We have to calculate by multiplying 5,000 and total number of months

7 0

4 years ago

If g(x)=4x^2-16 we’re shifted 9 united to the right and 1 down, what would the new equation be?

Inessa05 [86]

Shown in the graph

<h2>Explanation:</h2>

Using graph tools we can graph the function:

$g(x)=4x^2-16$

which is the red graph shown below. As you can see, this is a parabola. The rule for vertical and horizontal shifts is as follows:

$Let \ c \ be \ a \ positive \ real \ number. \ \mathbf{Vertical \ and \ horizontal \ shifts} \\ in \ the \ graph \ of \ y=f(x) \ are \ represented \ as \ follows:$

$\bullet \ Vertical \ shift \ c \ units \ \mathbf{upward}: \\ h(x)=f(x)+c \\ \\ \bullet \ Vertical \ shift \ c \ units \ \mathbf{downward}: \\ h(x)=f(x)-c \\ \\ \bullet \ Horizontal \ shift \ c \ units \ to \ the \ right \ \mathbf{right}: \\ h(x)=f(x-c) \\ \\ \bullet \ Horizontal \ shift \ c \ units \ to \ the \ left \ \mathbf{left}: \\ h(x)=f(x+c)$