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3 years ago

Find the slope of the line passing through the points (-2,-2) and (6,-2). slope

Mathematics

1 answer:

kap26 [50]3 years ago

4 0

Answer:

0/8

Step-by-step explanation:

Slope equals y 2 minus y 1 divided by x 2 minus x 1

-2-(-2)/6-(-2)

0/8

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The quotient of two numbers is 3 their product is 3 what are the two numbers

ruslelena [56]

Answer:

3 and 1

Step-by-step explanation:

They are the only numbers that could give the right answer.

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3 years ago

Can someone please help me with this algebra

Novay_Z [31]

Answer: d

Step-by-step explanation:

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3 years ago

Read 2 more answers

If AB= 2x+1 and BC=5x-14 Find AC

zloy xaker [14]

A=(2x+1)/B
C=(5x-14)/B

AC=(2x+1)/B * (5x-14)/B
AC=(10x² - 23x - 14)/BE

3 0

3 years ago

Malik grills a steak 45 minutes longer than he grills a serving of fish. The fish takes twice as long as the asparagus to grill.

stellarik [79]

Vasellasar26,

Penso che tu parli italiano, quindi ecco la risposta alla domanda in italiano. Malik griglia una bistecca 45 minuti in più rispetto a u.na porzione di pesce. Il pesce impiega il doppio del tempo per grigliare gli asparagi. Malik griglia i pomodori tagliati a metà per 3 minuti, che è 3 minuti in più rispetto a quando griglia gli asparagi. 3 33 Questa domanda è composta da 3 parti. Assicurati di completare tutte le parti. A Indicazioni: digita la tua risposta nella casella. Scrivi un'espressione che rappresenti il tempo durante il quale Malik griglia la bistecca se gli asparagi grigliano x minuti.

3 0

3 years ago

9. Alicia Martin's savings account has a principle of $1,200. It earns 6% interest compounded quartly

zavuch27 [327]

Answer:

$9) \$1236.27\,10)\,\$6451.07\, 11)\,\$10,152.87 \,12)\,\$907.95 \,13)\,\$4957.69$

Step-by-step explanation:

9) Since Alicia Martin's savings earns 6% quarterly for two quarters then:

$A=P(1+\frac{r}{n})^{nt}$ ⇒ Amount (A), Principle (P), rate (r) in decimal form, number of compoundings (n) a year and t, in year or its fractions.

$A=P(1+\frac{r}{n})^{nt}\Rightarrow A=1200(1+\frac{0.06}{4})^{4*\frac{1}{2}}\Rightarrow A=\$1236.27$

10) Aubrey Daniel's case:

$A=P(1+\frac{r}{n})^{nt}\Rightarrow A=5725(1+\frac{0.04}{4})^{4*3}\Rightarrow A\approx \$6451.07$

11) As for Angelo, similarly to Alicia.

$A=P(1+\frac{r}{n})^{nt}\Rightarrow A=9855(1+\frac{0.06}{4})^{4*\frac{1}{2}}\Rightarrow A\approx \$10,152.87$

12) Simpson's. For semiannual n=2

$A=P(1+\frac{r}{n})^{nt}\Rightarrow A=860(1+\frac{0.055}{2})^{2*1}\Rightarrow A\approx \$907.95$

13) Jana Lacey amount:

$A=P(1+\frac{r}{n})^{nt}\Rightarrow A=4860(1+\frac{0.04}{4})^{4*\frac{1}{2}}\Rightarrow A\approx \$4957.69$

6 0

3 years ago