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3 years ago

How to write 570,020 in word form

Mathematics

1 answer:

djyliett [7]3 years ago

7 0

Five hundred seventy thousand and twenty

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Determine the equation of the following polyromial that passes through point (0,6).

Ostrovityanka [42]

Answer:

Cubic polynomial has zeros at x=−1x=−1 and 22, is tangent to x−x−axis at x=−1x=−1, and passes through the point (0,−6)(0,−6).

So cubic polynomial has double zero at x=−1x=−1, and single zero at x=2x=2

f(x)=a(x+1)2(x−2)f(x)=a(x+1)2(x−2)

f(0)=−6f(0)=−6

a(1)(−2)=−6a(1)(−2)=−6

a=3a=3

f(x)=3(x+1)2(x−2)f(x)=3(x+1)2(x−2)

f(x)=3x3−9x−6

3 0

3 years ago

What were the other new Twelves talking about at school?

uranmaximum [27]

Answer:

B.about their first day of training

Step-by-step explanation:

4 0

3 years ago

Is the simplified form of 2square root of 3 + 3square root of 3 rational? Yes No

mariarad [96]

2 sqrt3 + 3 sqrt3

= 5 sqrt3

Since this contains the irrational sqrt3 it is irrational

4 0

3 years ago

Read 2 more answers

the midpoint is AB is M(3,-2). One endpoint is A(7,-9). Find the coordinates of the other endpoint B.

cestrela7 [59]

Answer:

The required points of the given line segment are ( - 1, - 5 ).

Step-by-step explanation:

Given that the line segment AB whose midpoint M is ( 3, -2 ) and point A is ( 7, - 9), then we have to find point B of the line segment AB -

As we know that-

If a line segment AB is with endpoints ( $x_{1}, y_{1}$ ) and ( $x_{2}, y_{2}$ )then the mid points M are-

M = ( $\frac{ x_{1} + x_{2} }{2}$ , $\frac{ y_{1} + y_{2} }{2}$ )

Here,

Let A ( 7, - 9 ), B ( x, y ) with midpoint M ( 3, - 2 ) -

then by the midpoint formula M are-

( 3, - 2 ) = ( $\frac{ 7 + x}{2}$ , $\frac{ - 9 + y}{2}$ )

On comparing x coordinate and y coordinate -

We get,

( $\frac{ 7 + x}{2}$ = 3 , $\frac{ - 9 + y}{2}$ = - 2)

( 7 + x = 6, - 9 + y = - 4 )

( x = 6 - 7, y = - 4 + 9 )

( x = - 1, y = -5 )

Hence the required points A are ( - 1, - 5 ).

We can also verify by putting these points into Midpoint formula.

8 0

3 years ago

Solve for x.

Tamiku [17]

The answer to the question is a

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3 years ago