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marissa [1.9K]
3 years ago
5

if the ratio of the volume of two cubes is 1 : 8 , then find the ratio of the total surface area of the two cubes​

Mathematics
1 answer:
vivado [14]3 years ago
3 0

Answer:

V = L^3      where v is volume and L the length of one side

A = 6 * L^2    total area of cube with side L

A = 6 * V^2/3      area of cube expressed in V

A2 / A1 = (V2 / V1)^2/3       6 cancels

A2 / A1 = 8^2/3 = 4      ratio of areas

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Find the terms, coefficients, and constants of 4x+x+17
andreyandreev [35.5K]

Answer:

17 and x=constant,

4x=coefficient

hope this helps

have a good day :)

Step-by-step explanation:

4 0
3 years ago
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I will give brainlest for the right answer. Please don't just make up a random thing. PLEASE!
Alexxx [7]

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30( \frac{1}{2} x - 2) + 40( \frac{3}{4} y - 4) =  \\

(30 \times  \frac{1}{2} x) -( 30 \times 2 )+ (40 \times  \frac{3}{4} y )- (40 \times 4 )=  \\

15x - 60 + 30y - 160 =  \\

15x + 30y - 220

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The correct answer is Option Three .

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6 0
3 years ago
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Help help help help pls
Monica [59]

Answer:

\theta = 82.2^\circ

Step-by-step explanation:

Let \  \angle BAC = \theta

Opposite = BC ,

Adjacent = AB = x = 3 ,

Hypotenuse = AC = y = 22

<em><u>Using trigonometric ratios.</u></em>

sin \theta = \frac{opposite}{hypotenuse }\\\\cos \theta = \frac{adjacent}{hypotenuse}\\\\tan \theta = \frac{opposite}{adjacent}

Since we have adjacent and hypotenuse we use cosine's  ratio

to find the angle.

           cos \theta = \frac{x}{y} = \frac{3}{22} \\\\\theta = cos^{-1} \frac{3}{22} = 82.16 = 82.2^\circ

6 0
3 years ago
(40 points + Brainliest)
Sladkaya [172]
The answer would be B because y=mx+b
7 0
3 years ago
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On my paper I got a 96 but I want a 100 so I am doing corrections on one problem and I need help please. I tried 5 but that wasn
Scorpion4ik [409]
16 students out of 20
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