Question

Factorise the given expressions : a) (6p2 – 36p + 30) b) (256 − 64y + 4y2 )

Answer 1

Answer:

a) Factorizing $6p^2 - 36p + 30$ we get $6(p-5)(p-1)$

b) Factorizing $4y^2-64y+256$ we get $4(y-8)(y-8)$

Step-by-step explanation:

Factorise the given expressions :

a) $6p^2 - 36p + 30$

First we take 6 common:

$6p^2-36p+30\\=6(p^2-6p+5)\\=6(p^2-5p-p+5)\\=6(p(-5)-1(p-5))\\=6(p-5)(p-1)$

So, factorizing $6p^2 - 36p + 30$ we get $6(p-5)(p-1)$

b) $256 -64y + 4y^2$

Rearranging terms:

$4y^2-64y+256$

Taking 4 common

$4(y^2-16y+64)\\4(y^2-8y-8y+64)\\4(y(y-8)-8(y-8))\\4(y-8)(y-8)$

So, factorizing $4y^2-64y+256$ we get $4(y-8)(y-8)$