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damaskus [11]
3 years ago
10

A box contains four red balls and eight black balls. Two balls are randomly chosen from the box, and are not

Mathematics
2 answers:
Julli [10]3 years ago
3 0

Step-by-step explanation:

Total balls = 12

Probability of 2 black balls = 2/ 8 = 1/4

Probability of 2 red balls = 2/4 = 1/2

Probability of both red and black = 2/12 = 1/6

Dmitry_Shevchenko [17]3 years ago
3 0

Answer:

P(B) = 8/12

P(R | B) = 4/11

P(B ∩ R) = 8/33

The probability that the first ball chosen is black and the second ball chosen is red is about 24% percent.

Step-by-step explanation:

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