Step-by-step explanation:
Total balls = 12
Probability of 2 black balls = 2/ 8 = 1/4
Probability of 2 red balls = 2/4 = 1/2
Probability of both red and black = 2/12 = 1/6
Answer:
P(B) = 8/12
P(R | B) = 4/11
P(B ∩ R) = 8/33
The probability that the first ball chosen is black and the second ball chosen is red is about 24% percent.
b
(2x + 6) x (-5x -9)
-10x^2 -18 - 30 -54
-10x^2 - 38 - 54
We need the image. :/
