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Phantasy [73]
3 years ago
10

What is the value of in the equation

Mathematics
1 answer:
GalinKa [24]3 years ago
7 0

Answer:

in what equation u forgot to put a picture

Step-by-step explanation:

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Find the distance between the points A (13, 2) and B (7, 10).
Aliun [14]

Answer:

10

Step-by-step explanation:

d = 10

For:

(X1, Y1) = (13, 2)

(X2, Y2) = (7, 10)

Distance Equation Solution:

d=(7−13)2+(10−2)2−−−−−−−−−−−−−−−−−√

d=(−6)2+(8)2−−−−−−−−−−√

d=36+64−−−−−−√

d=1–√00

d=10

4 0
3 years ago
If f(x)=7x+8 and g(x)=x^4, what is (g°f)(0)​
Lina20 [59]
G(f(x))= (7x+8)^4
g(f(x))= (7(0)+8)^4
=(0+8)^4
=8^4
=8•8•8•8
=4,096
8 0
3 years ago
Read 2 more answers
The base of a right circular cylinder has a diameter of 5.00 inches. Sally measured the circumference of the base cylinder and r
LUCKY_DIMON [66]

Answer:

The percent of error in her measurement is 1.3%

Step-by-step explanation:

we know that

The circumference of a circle is equal to

C=\pi D

where

D is the diameter

we have

D=5\ in

assume

\pi=3.14

substitute

C=(3.14)(5)=15.7\ in ----> This value represent the 100% (theoretical value)

Find the difference between the theoretical value and the measured value

15.7-15.5=0.2\ in

Find the percentage by proportion

15.7/100=0.2/x\\ x=100*0.2/15.7\\ x=1.3\%

4 0
4 years ago
There is a bag filled with 4 blue, 3 red and 5 green marbles.
zhannawk [14.2K]

Answer:

You are selecting marbles with replacement. The marble selections (trials) are independent and the marble selection follows the binomial distribution.

The probability of selecting a red marble the first time is 1313.

(This is because 4 out of 12 marbles are red and412412 reduces to 1313.

The probability of selecting a red marble the second time is 1313.

The marble selections are independent and you can multiply the two probabilities to get the following:

probability of getting 2 reds = (13)2(13)2

=19=19.

So the probability of getting two reds is 1919.

7 0
3 years ago
What is the measure of the hypotenuse?
SOVA2 [1]
<h2><em>Answer:</em></h2><h3><em>1</em><em>3</em></h3>

<em>solution \\ hypotenuse = x \\ base = 12 \\ perpendicular = 5 \\ using \: pythagoras \: theorem \\  {h}^{2}  =  {p}^{2}  +  {b}^{2}  \\ or \:  {x}^{2}  =  {5}^{2}  +  {12}^{2}  \\ or \:  {x}^{2}  = 25  + 144 \\ or \:  {x}^{2}  = 169 \\ or \: x =  \sqrt{169}  \\ x = 13 \\</em>

<em>hope </em><em>it</em><em> helps</em><em>.</em><em>.</em><em>.</em><em>.</em>

<em>Good </em><em>luck</em><em> on</em><em> your</em><em> assignment</em>

3 0
3 years ago
Read 2 more answers
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