Question

Find a equation of a line that is perpendicular to y=-4x+3 and passes through the point (4,-1)

Answer 1

Answer:

y = (-1/4)x

Step-by-step explanation:

the factor of x is in a line equation the slope of the line.

it residents actually the ratio of y/x.

in our original equation that means that for every change of x by 1 unit y changes by 4 units (actually -4 units) => -4/1 ratio.

a perpendicular line just reverses that ratio.

now, x had to change by 4 units for y to change by 1 unit (actually -1 unit)

=> -1/4

so, our wanted line equation must be in the form of

y = (-1/4)x + c

c is the offset of the line from the (0,0) point in y direction.

so, what is c ?

now we use the information of the point that is stored to be in that line : (4,-1)

=> -1 = (-1/4)×4 + c

=> -1 = -1 + c

=> c = 0

therefore, the desired line is

y = (-1/4)x