Question

An art project has an area of 63.6 square inches. What is the width, in inches, of the project?

Answer 1

Answer:

Option C . 5.3 in

Step-by-step explanation:

The complete question is

An art project has an area of 63.6 square inches. What is the width, in inches, of the project?

A rectangle is shown divided into 4 smaller rectangles that are related to the size of the edges. The top edge is labeled 10 inches and 2 inches, above the top two rectangles. The top two rectangles are much larger than the bottom two rectangles

Let

x ----> the length of the art project in inches

y ----> the width of the art project in inches

we know that

The area of the rectangular art project is equal to

$A=xy$

we have

$A=63.6\ in^2$

so

$63.6=xy$ ----> equation A

$x=10+2=12\ in$

substitute the value of x in the equation A

$63.6=(12)y$

solve for y

$y=63.6/12\\y=5.3\ in$