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aleksandr82 [10.1K]
3 years ago
8

Help is needed please!!!!

Mathematics
1 answer:
jeka57 [31]3 years ago
8 0

Answer:

31/20

Step-by-step explanation:

You need to plug in x as y-3.

so instead of 10x+10y=1 it is 10(y-3)+10y=1

Then just simplify the equation to find the value of y

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D-1/2=5/12 what is d??
EleoNora [17]

Answer:

d = \frac{11}{12}

Step-by-step explanation:

1) To solve for d, isolate it in the equation. So, to get rid of the -\frac{1}{2} with the d, add \frac{1}{2} to both sides.

d-\frac{1}{2}  = \frac{5}{12} \\d - \frac{1}{2} +\frac{1}{2} = \frac{5}{12} + \frac{6}{12} \\d = \frac{11}{12}

Thus, d = \frac{11}{12}.

6 0
3 years ago
A rectangular block has square base of area 64 cm². If the thickness of the block is 5 cm, find its total surface area. ​
Andrej [43]

Answer:

total surface area of cube is <u>6 * area of one side</u>

therefore area of one side is given 64cm^2

thickness is also given 5cm .

TSA is 64*5 = 320cm^2

hope it is helpful

4 0
3 years ago
Read 2 more answers
Please help me solve this problem ASAP
DiKsa [7]

\bold{\huge{\blue{\underline{ Solution }}}}

<h3><u>Given </u><u>:</u><u>-</u></h3>

  • <u>The </u><u>right </u><u>angled </u><u>below </u><u>is </u><u>formed </u><u>by </u><u>3</u><u> </u><u>squares </u><u>A</u><u>, </u><u> </u><u>B </u><u>and </u><u>C</u>
  • <u>The </u><u>area </u><u>of </u><u>square </u><u>B</u><u> </u><u>has </u><u>an </u><u>area </u><u>of </u><u>1</u><u>4</u><u>4</u><u> </u><u>inches </u><u>²</u>
  • <u>The </u><u>area </u><u>of </u><u>square </u><u>C </u><u>has </u><u>an </u><u>of </u><u>1</u><u>6</u><u>9</u><u> </u><u>inches </u><u>²</u>

<h3><u>To </u><u>Find </u><u>:</u><u>-</u></h3>

  • <u>We </u><u>have </u><u>to </u><u>find </u><u>the </u><u>area </u><u>of </u><u>square </u><u>A</u><u>? </u>

<h3><u>Let's </u><u>Begin </u><u>:</u><u>-</u><u> </u></h3>

The right angled triangle is formed by 3 squares

<u>We </u><u>have</u><u>, </u>

  • Area of square B is 144 inches²
  • Area of square C is 169 inches²

<u>We </u><u>know </u><u>that</u><u>, </u>

\bold{ Area \: of \: square =  Side × Side }

Let the side of square B be x

<u>Subsitute </u><u>the </u><u>required </u><u>values</u><u>, </u>

\sf{ 144 =  x × x }

\sf{ 144 =  x² }

\sf{ x = √144}

\bold{\red{ x = 12\: inches }}

Thus, The dimension of square B is 12 inches

<h3><u>Now, </u></h3>

Area of square C = 169 inches

Let the side of square C be y

<u>Subsitute </u><u>the </u><u>required </u><u>values</u><u>, </u>

\sf{ 169 =  y × y }

\sf{ 169 =  y² }

\sf{ y = √169}

\bold{\green{ y = 13\: inches }}

Thus, The dimension of square C is 13 inches.

<h3><u>Now, </u></h3>

It is mentioned in the question that, the right angled triangle is formed by 3 squares

The dimensions of square be is x and y

Let the dimensions of square A be z

<h3><u>Therefore</u><u>, </u><u>By </u><u>using </u><u>Pythagoras </u><u>theorem</u><u>, </u></h3>

  • <u>The </u><u>sum </u><u>of </u><u>squares </u><u>of </u><u>base </u><u>and </u><u>perpendicular </u><u>height </u><u>equal </u><u>to </u><u>the </u><u>square </u><u>of </u><u>hypotenuse </u>

<u>That </u><u>is</u><u>, </u>

\bold{\pink{ (Perpendicular)² + (Base)² = (Hypotenuse)² }}

<u>Here</u><u>, </u>

  • Base = x = 12 inches
  • Perpendicular = z
  • Hypotenuse = y = 13 inches

<u>Subsitute </u><u>the </u><u>required </u><u>values</u><u>, </u>

\sf{ (z)² + (x)² = (y)² }

\sf{ (z)² + (12)² = (169)² }

\sf{ (z)² + 144 = 169}

\sf{ (z)² = 169 - 144 }

\sf{ (z)² = 25}

\bold{\blue{ z = 5 }}

Thus, The dimensions of square A is 5 inches

<h3><u>Therefore</u><u>,</u></h3>

Area of square

\sf{ = Side × Side }

\sf{ = 5 × 5  }

\bold{\orange{ = 25\: inches }}

Hence, The area of square A is 25 inches.

6 0
2 years ago
Help please?? <br><br>Answer:
Sveta_85 [38]
1. Yes, a regular hexagon can be drawn using rotations.
2.To find the answer, first find the number of sides of a hexagon. A hexagon has six sides.
Divide 360 by 6 = 360/6=60 degrees.
So the angle of rotation for a point on the circle for drawing a regular hexagon is 60 degrees.


3 0
3 years ago
2 members of the 5-member math study group will present their project to the class. How many combinations of 2 members are possi
klio [65]

Answer:

2

Step-by-step explanation:

(,)=?

(,)=(5,2)

=5!(2!(5−2)!)

=5!2!×3!

= 10

4 0
3 years ago
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