3(-2x + 6) - x + 3 = 0
-6x + 18 - x + 3 = 0
-7x + 18 + 3 = 0
-7x +21 = 0
-7x = -21
-7x/-7 = -21/-7
x = 3
y = -2(3) + 6
y = -6 + 6
y = 0
x= 3 y = 0
Answer:
D
Step-by-step explanation:
Given
C = 2πr ( isolate r by dividing both sides by 2π )
= r → D
Answer: (3) 3 liters (4) Woodwind = 180, Brass = 90, Percussion = 10
<u>Step-by-step explanation:</u>
3) Set up a table. Multiply across and add down to create the equation.
![\begin{array}{l|c|c|c}&\underline{\quad Qty\quad}&\underline{\quad \% \quad}&\underline{\quad Qty \times \% \quad}\\\text{Whole Milk}&4&.035&4(.035)\\\underline{\text{Skim Milk\quad}}&\underline{\qquad x\qquad} &\underline{\qquad 0\qquad}&\underline{\qquad x(0)\qquad}\\\text{Mixture}&4+x&.02&4(.035)+x(0)\\\end{array}\\\\\\.\qquad \qquad (4+x)(.02)=4(.035)+x(0)\\\\.\qquad \qquad (4+x)(.02)=.14\\\\.\qquad \qquad 4+x\quad \qquad =7\qquad \longrightarrow \text{divided both sides by .02}\\](https://tex.z-dn.net/?f=%5Cbegin%7Barray%7D%7Bl%7Cc%7Cc%7Cc%7D%26%5Cunderline%7B%5Cquad%20Qty%5Cquad%7D%26%5Cunderline%7B%5Cquad%20%5C%25%20%5Cquad%7D%26%5Cunderline%7B%5Cquad%20Qty%20%5Ctimes%20%5C%25%20%5Cquad%7D%5C%5C%5Ctext%7BWhole%20Milk%7D%264%26.035%264%28.035%29%5C%5C%5Cunderline%7B%5Ctext%7BSkim%20Milk%5Cquad%7D%7D%26%5Cunderline%7B%5Cqquad%20x%5Cqquad%7D%20%26%5Cunderline%7B%5Cqquad%200%5Cqquad%7D%26%5Cunderline%7B%5Cqquad%20x%280%29%5Cqquad%7D%5C%5C%5Ctext%7BMixture%7D%264%2Bx%26.02%264%28.035%29%2Bx%280%29%5C%5C%5Cend%7Barray%7D%5C%5C%5C%5C%5C%5C.%5Cqquad%20%5Cqquad%20%284%2Bx%29%28.02%29%3D4%28.035%29%2Bx%280%29%5C%5C%5C%5C.%5Cqquad%20%5Cqquad%20%284%2Bx%29%28.02%29%3D.14%5C%5C%5C%5C.%5Cqquad%20%5Cqquad%204%2Bx%5Cquad%20%5Cqquad%20%3D7%5Cqquad%20%5Clongrightarrow%20%5Ctext%7Bdivided%20both%20sides%20by%20.02%7D%5C%5C)
x = 3 ---> subtracted 4 from both sides
4)
Woodwind: 2x
Brass: x
<u>Percussion: x - 80</u>
TOTAL: 4x - 80 = 280
4x = 360 ----> added 80 to both sides
x = 90 ---> divided 4 from both sides
Woodwind: 2x ---> 2(90) = 180
Brass: x ---> 90
Percussion: x - 80 ---> 90 - 80 = 10
For solving these equation, it is important to isolate the variable to then solve it.
In this first equation,
3(4+x)=x+6
12+3x=x+6
12+2x=6
2x=-6
x=-3
to prove this, just substitute x value back into equation;
3(4-3)=-3+6
3(1)=3
3=3
Same for the next equations;
1+2x-x=x-5+x
1+x=2x-5
1=x-5
6=x
Then substitute this value back into equation;
1+2(6)-6=6-5+6
1+12-6= 12-5
7=7
If you would like to write x = 1/3 * y in general form, you can do this using the following steps:
<span>The general form of the equation is: </span>ax + by + c = 0.
x = 1/3 * y
x - 1/3 * y = 0
The correct result would be <span>x - 1/3 * y = 0.</span>