Answer:
4 minutes.
Explanation:
The rate of flow from the tap is 2 gallons every six second
which comes out to be 1 gallons per 3 seconds.
so for 80 gallons we can simply
3 * 80 = 240 which is 240 seconds.
Thus it would take 4 minutes to fill up the 80 gallon tub.
Answer:
A. $405 million
B. $332 million
Explanation:
A. Calculation for How much was Carter's net income for 2016
Using this formula
2016 Net income=Sales revenue - Cost of goods sold - Other expenses
Let plug in the formula
2016 Net income= $900 million - $270 million - $225 million
2016 Net income = $405 million
Therefore How much was Carter's net income for 2016 is $405 million
B. Calculation for How much was Carter's cash balance at the end of 2016
Using this formula
2016 Ending cash balance =Beginning balance + Cash receipts - Payments
Let plug in the formula
2016 Ending cash balance=$ 110 millon + $872 million- $375million - $275million
2016 Ending cash balance= $332million
How much was Carter's cash balance at the end of 2016 is $332million
Answer and Explanation:
Given:
Total car = 200
Rate = $29
Computation:
Total increase in rate = a
So , Total decrees in car = 5a
Total income (y) = [200-5a][29+a]
y = 5,800 + 200a - 145a - 5a²
y = 5,800 + 55a - 5a²
y' = dy / da [5,800 + 55a - 5a²]
y' = -10a + 55
in which , y' = 0
0 = -10a + 55
a = 5.5
So , Maximum rate = $ [29+5.5]
Maximum rate = $34.5
maximum income = 5,800 + 55(5.5)- 5(5.5)²
maximum income = 5,800 + 302.5 - 151.25
maximum income = $5951.25
Answer:
12.93%
Explanation:
Given that the amount of 300 is invested for 3 years, while the amount of 100 is invested for 2 years and 100 is invested for 1 year.
also amount accumulated in three years = 800
Applying the formula to find the future value we get
300(1+r)^3 + 200(1+r)^2 + 100(1+r) = 800
which can be further simplified to
300r^3+1100r^2+1400r+600=800
where, r is the effective rate of interest which we have to find out
The above equation is cubic in r, so to solve this we can use equation solver. When we put this equation in equation solver we get
r = 0.12926
r ≅ 0.1293
Therefore, effective rate of interest = 12.93%
