Question

PLEASE HELP< ILL GIVE 45 POINTS AFTER YOU ANSWER!!!

Answer 1

Given:

Vertices of △XYZ are X(-4,6), Y(6,1) and Z(1,1).

To find:

The vertices of ∆X′Y′Z′.

Solution:

According to the question, △XYZ is translated 3 units up to form the image ∆X′Y′Z′, so rule of translation is defined as

$(x,y)\to (x,y+3)$

Now,

$X(-4,6)\to X'(-4,6+3)$

$X(-4,6)\to X'(-4,9)$

Similarly,

$Y(6,1)\to Y'(6,1+3)$

$Y(6,1)\to Y'(6,4)$

and,

$Z(1,1)\to Z'(1,1+3)$

$Z(1,1)\to Z'(1,4)$

Therefore, $X'=(-4,9),Y'=(6,4),Z'=(1,4)$.