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Elden [556K]
3 years ago
8

Help I need help on this question its kinda confusing to me..

Mathematics
1 answer:
Kruka [31]3 years ago
4 0
B the origin is the very middle of a graph , the intercept of the x axis and the the y axis
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Write 4^6 as a power of 2.
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4^6= 24
24 power 2=24x24= 576
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Binary is best interpreted by a computer because
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Anita has $300 in her savings account that earns 5% annually. The
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What is the value of x ??
ruslelena [56]

Answer:

A

Step-by-step explanation:

The Tangent-Secant Exterior Angle Measure Theorem states that if a tangent and a secant or two tangents/secants intersect outside of a circle, then the measure of the angle formed by them is half of the difference of the measures of its intercepted arcs. Basically, what that means here is that x equals half of the difference of 30\textdegree and the measure of the unlabeled arc.

First, we need to find the measure of the unlabeled arc, since we can't find x without it. We know that the measure of the full arc formed by the circle is 360\textdegree, so the measure of the unlabeled arc must be 360-30-100-100=130\textdegree by the Arc Addition Postulate.

Now, we can find x. Using all of the information known, we can solve for x like this:

\\x=\frac{1}{2} (130\textdegree-30\textdegree)\\=\frac{1}{2} (100\textdegree)\\=50\textdegree

Hope this helps!

5 0
3 years ago
A ship leaves port at 1:00 P.M. and travels S35°E at the rate of 27 mi/hr. Another ship leaves the same port at 1:30 P.M. and tr
Len [333]

To solve this problem you must apply the proccedure shown below:

1. You must apply the Law of Cosines, as you can see in the figure attached. Then:

- The first ship travels at 27 mi/hr in for two hours. Therefore, the side a is:

a=(27 mi/hr)(2 hr)=54mi

- The second ship travels at 18 mi/hr for 1.5 hours. Therefore, the side b is:

b=(18mi/hr)(1.5hr)=27mi

- Now, you can calculate c:

c=\sqrt{54^{2}+27^{2}-2(54)(27)Cos(55)}=44 mi

The answer is: 44 miles

8 0
3 years ago
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