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Elden [556K]
3 years ago
8

Help I need help on this question its kinda confusing to me..

Mathematics
1 answer:
Kruka [31]3 years ago
4 0
B the origin is the very middle of a graph , the intercept of the x axis and the the y axis
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Cinderella currently does chores for 120 minutes per day. Her evil step-mother wants her to do chores for 200 minutes each day.
jarptica [38.1K]

Answer:

B.

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
18. A simple random sample of size n is drawn from a population that is normally distributed. The sample mean, x, is found to be
avanturin [10]

Answer:

a. =50 ± 4.67

b. =50 ± 4.81  

decreasing the sample size increase the margin of error

c. =50 ± 3.51

decreasing the confidence level reduced the margin of error

d. No.  because the confidence interval coefficient is gotten from the table of normal distribution of Z value.  therefore the confidence interval is only used for normal distributed population

Step-by-step explanation:

given

The sample mean, x, = 50,

the sample standard deviation, s, = 8.

a. Construct a 98% confidence interval for m if the sample size, n, is 20

for a 98% confidence interval of an infinite population, thus for a sample of size N and mean x, drawn from an infinite population having a standard deviation of σ, the mean value of the population is estimated to by:

x± 2.33σ /√N

for a confidence level of 98%, Zc = 2.33 gotten from the table of confidence interval.

This indicates that the mean value of the population lies between

50- ( 2.33*8 /√20)      and 50+ ( 2.33*8 /√20)

with 98% confidence in this prediction.

=50 ± 4.67

=45.33 or 54.67

(b) Construct a 98% confidence interval for m if the sample size, n, is 15.

using the same method as above

x± 2.33σ /√N

This indicates that the mean value of the population lies between

50- ( 2.33*8 /√15)      and 50+ ( 2.33*8 /√15)

=50 ± 4.81

=45.19 or 54.81

decreasing the sample size increase the margin of error

(c) Construct a 95% confidence interval for m if the sample size, n, is 20. Compare the results to those obtained in part

95% confidence interval =1.96 (gotten from table of confidence coefficient)

using x±1.96 σ /√N

This indicates that the mean value of the population lies between

50- (1.96 *8 /√20)      and 50+ (1.96 *8 /√20)

=50 ± 3.51

=46.49 or 53.51

c. decreasing the confidence level reduced the margin of error

(d) Could we have computed the confidence intervals in parts (a)–(c) if the population had not been normally distributed?

No.  because the confidence interval coefficient is gotten from the table of normal distribution of Z value.  therefore the confidence interval is only used for normal distributed population

7 0
3 years ago
Can someone please help me with this math question? It should be attached. <br> Thanks!
Ad libitum [116K]
If you multiple the net by 2, you will get 2720, and dividing it from 940, you will get 35%. B is the correct answer. :)
8 0
3 years ago
Solve |x+ 3|- 1 = (x + 2)^2 by graphing.<br> The solutions are x =<br> and x =
Setler [38]

9514 1404 393

Answer:

  x = -2, x = -1

Step-by-step explanation:

A graphing calculator solves this nicely, as shown in the attachment.

  x = -2, x = -1

__

The given equation resolves to two equations.

<u>x+3 < 0</u>

  -(x +3) -1 = (x +2)^2

  x^2 +5x +7 = 0

Checking the discriminant, we find ...

  b^2 -4ac = (5)^2 -4(1)(7) = 25 -28 = -3

There are only complex solutions to this equation.

__

<u>x+3 ≥ 0</u>

  x +3 -1 = (x +2)^2

  (x +2)^2 -(x +2) = 0 . . . .subtract x+2

  (x +2)(x +2 -1) = 0 . . . . . factor

Solutions are values of x that make these factors zero.

  x +2 = 0   ⇒   x = -2

  x +1 = 0   ⇒   x = -1

<em>Domain Check</em>

  x +3 = -2 +3 = 1 > 0 . . . . as required.

5 0
3 years ago
What is 4x+2(3x7)= if x=5
Sedbober [7]

4x + 2(3\cdot7) = ?

Now we must solve this equation if x = 5. To do so we must substitute:

4(5)+2(3\cdot7)\\

Using PEMDAS we will solve for the parenthesis first.

4(5)+2(21)

Multiply:

20+(42)

Add:

20+42=62

Final answer: 62

4 0
3 years ago
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