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Sever21 [200]
3 years ago
12

Pague 325 por un saco, una camisa y una corbata. El saco costó 80 más que la camisa y la corbata 25 menos que el saco.Hallar los

precios de cada uno
Mathematics
1 answer:
Anon25 [30]3 years ago
6 0
Add all then that is 345
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Residences of U.S. Citizens According to the U.S. Census, 67.5% of the U.S. population were born in their state of residence. In
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Answer:

P(X < 126) = 0.0418

Step-by-step explanation:

To solve this question, we use the binomial approximation to the normal to solve this question.

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

Can be approximated to a normal distribution, using the expected value and the standard deviation.

The expected value of the binomial distribution is:

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Normal probability distribution

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Z = \frac{X - \mu}{\sigma}

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When we are approximating a binomial distribution to a normal one, we have that \mu = E(X), \sigma = \sqrt{V(X)}.

Sample of 203, 67.5% of the U.S. population were born in their state of residence.

This means that n = 203, p = 0.675

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\mu = E(X) = np = 203*0.675 = 137.025

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What is the probability that fewer than 126 were born in their state of residence?

Using continuity correction, this is P(X < 126 - 0.5) = P(X < 125.5), which is the pvalue of Z when X = 125.5. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{125.5 - 137.025}{6.67}

Z = -1.73

Z = -1.73 has a pvalue of 0.0418

So

P(X < 126) = 0.0418

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