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3 years ago

HELPPP NEED IN THE NEXT 10 MINSSS!!!!

Mathematics

2 answers:

Mice21 [21]3 years ago

6 0

Answer:

15.6

Step-by-step explanation:

the traingle is right so u have to apply the pythagorean theorem to find x so x^2=10^2+12^2=244

so x=15.6

Ksivusya [100]3 years ago

4 0

Step-by-step explanation:

hope it's helpful ❤❤❤❤

THANK YOU.

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The volume of a cube related to the area of a face by the formula V =A^3/2. What is the volume of a cube whose face has an area

11111nata11111 [884]

Answer:

Volume = 125 mm^3

Step-by-step explanation:

Here, we want to get the volume of the cube

What we have to do here is to substitute the value of the area

We have this as

V = 25^(3/2)

V = (√25)^3

V = 5 * 5 * 5 = 125 mm^3

6 0

3 years ago

Two different radioactive isotopes decay to 10% of their respective original amounts. Isotope A does this in 33 days, while isot

Andrews [41]

Answer:

The approximate difference in the half-lives of the isotopes is 66 days.

Step-by-step explanation:

The decay of an isotope is represented by the following differential equation:

$\frac{dm}{dt} = -\frac{t}{\tau}$

Where:

$m$ - Current mass of the isotope, measured in kilograms.

$t$ - Time, measured in days.

$\tau$ - Time constant, measured in days.

The solution of the differential equation is:

$m(t) = m_{o}\cdot e^{-\frac{t}{\tau} }$

Where $m_{o}$ is the initial mass of the isotope, measure in kilograms.

Now, the time constant is cleared:

$\ln \frac{m(t)}{m_{o}} = -\frac{t}{\tau}$

$\tau = -\frac{t}{\ln \frac{m(t)}{m_{o}} }$

The half-life of a isotope ( $t_{1/2}$ ) as a function of time constant is:

$t_{1/2} = \tau \cdot \ln2$

$t_{1/2} = -\left(\frac{t}{\ln\frac{m(t)}{m_{o}} }\right) \cdot \ln 2$

The half-life difference between isotope B and isotope A is:

$\Delta t_{1/2} = \left| -\left(\frac{t_{A}}{\ln \frac{m_{A}(t)}{m_{o,A}} } \right)\cdot \ln 2+\left(\frac{t_{B}}{\ln \frac{m_{B}(t)}{m_{o,B}} } \right)\cdot \ln 2\right|$

If $\frac{m_{A}(t)}{m_{o,A}} = \frac{m_{B}(t)}{m_{o,B}} = 0.9$ , $t_{A} = 33\,days$ and $t_{B} = 43\,days$ , the difference in the half-lives of the isotopes is: