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3 years ago

HELP!!!! The measure of side BC =

Mathematics

1 answer:

Wittaler [7]3 years ago

4 0

Answer:

Step-by-step explanation:

Using the cosine ratio and the exact value

cos45° = $\frac{\sqrt{2} }{2}$ , then

cos45° = $\frac{adjacent}{hypotenuse}$ = $\frac{BC}{AC}$ = $\frac{BC}{n}$ = $\frac{\sqrt{2} }{2}$ ( cross- multiply )

2BC = n $\sqrt{2}$ ( divide both sides by 2 )

BC = $\frac{n\sqrt{2} }{2}$ → D

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