Answer:
The answer to your question is: 20°
Step-by-step explanation:
Data
m∠XZY = 40
m∠XZB = 20
Process
1.- Find the measure of ∠ XAB
∠XAB = 40° because AB ║ YZ
2.- Find the measure of ∠ZAB
∠ZAB + ∠XAB = 180
∠ZAB = 180 - ∠XAB
∠ZAB = 180 - 40
∠ZAB = 140°
3.- Find the measure of ∠ABZ
The sum of the internal angles in a triangle equals 180°
∠AZB + ∠ZAB + ∠ABZ = 180
20° + 140° + ∠ABZ = 180
∠ABZ = 180 - 20 - 140
∠ABZ = 20°
Let's begin by listing out the information given to us:
8 am
airplane #1: x = 80870 ft, v = -450 ft/ min
airplane #2: x = 5000 ft, v = 900ft/min
1.
We must note that the airplanes are moving at a constant speed. The equation for the airplanes is given by:

2.
We equate equations 1 & 2 to get the time both airlanes will be at the same elevation. We have:

3.
The elevation at that time (when the elevations of the two airplanes are the same) is given by substituting the value of time into equations 1 & 2. We have:
i think it's t=0.2 Hope it helps:)
Answer:
the correct answer is A, (The hiker is 371 m below Kalpana.)
Answer:
This is what I got 6/10
Step-by-step explanation:
hope this helps