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diamong [38]
2 years ago
12

Can someone pls help me

Mathematics
2 answers:
Novosadov [1.4K]2 years ago
8 0
9(2n + 1)

Distribute 9 to the terms in the brackets.

18n + 9

Add = 0 to solve for x

18n + 9 = 0

Move 9 to the other side by subtracting

18n = -9

Divide by 18 on both sides

n = -9/18

Simplify

n = -1/2

In decimal form the answer can also be -0.5 depending on your question.

Hope this helped!


anygoal [31]2 years ago
6 0

Answer:

Sorry that I cant help.

But have a good rest of your dayFollow if you liked this.

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Step-by-step explanation:

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3 years ago
Your friend borrows $7500 to buy an all-terrain vehicle (ATV). The simple annual interest rate is 6%. She pays off the loan afte
e-lub [12.9K]

Answer:

$162.50

Explanation:

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1 year ago
Engineers must consider the diameters of heads when designing helmets. The company researchers have determined that the populati
IrinaK [193]

Answer:

1. The minimum head breadth that will fit the clientele is of 3.95-in.

2. The maximum head breadth that will fit the clientele is of 9.25-in.

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Mean of 6.6-in and a standard deviation of 1.1-in.

This means that \mu = 6.6, \sigma = 1.1

1. What is the minimum head breadth that will fit the clientele?

The 0.8th percentile, which is X when Z has a p-value of 0.008, so X when Z = -2.41.

Z = \frac{X - \mu}{\sigma}

-2.41 = \frac{X - 6.6}{1.1}

X - 6.6 = -2.41*1.1

X = 3.95

The minimum head breadth that will fit the clientele is of 3.95-in.

2. What is the maximum head breadth that will fit the clientele?

The 100 - 0.8 = 99.2nd percentile, which is X when Z has a p-value of 0.992, so X when Z = 2.41.

Z = \frac{X - \mu}{\sigma}

2.41 = \frac{X - 6.6}{1.1}

X - 6.6 = 2.41*1.1

X = 9.25

The maximum head breadth that will fit the clientele is of 9.25-in.

8 0
2 years ago
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vovangra [49]

Answer:

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4 0
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Speed = 90km/hr
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6 0
2 years ago
Read 2 more answers
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