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2 years ago

Can someone pls help me

Mathematics

2 answers:

Novosadov [1.4K]2 years ago

8 0

9(2n + 1)

Distribute 9 to the terms in the brackets.

18n + 9

Add = 0 to solve for x

18n + 9 = 0

Move 9 to the other side by subtracting

18n = -9

Divide by 18 on both sides

n = -9/18

Simplify

n = -1/2

In decimal form the answer can also be -0.5 depending on your question.

Hope this helped!

anygoal [31]2 years ago

6 0

Answer:

Sorry that I cant help.

But have a good rest of your dayFollow if you liked this.

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Can someone help me.

Sauron [17]

Answer:

The answer to your question is: 20°

Step-by-step explanation:

Data

m∠XZY = 40

m∠XZB = 20

Process

1.- Find the measure of ∠ XAB

∠XAB = 40° because AB ║ YZ

2.- Find the measure of ∠ZAB

∠ZAB + ∠XAB = 180

∠ZAB = 180 - ∠XAB

∠ZAB = 180 - 40

∠ZAB = 140°

3.- Find the measure of ∠ABZ

The sum of the internal angles in a triangle equals 180°

∠AZB + ∠ZAB + ∠ABZ = 180

20° + 140° + ∠ABZ = 180

∠ABZ = 180 - 20 - 140

∠ABZ = 20°

7 0

2 years ago

At 8:00 am, here's what we know about two airplanes: Airplane #1 has an elevation of 80870 ft and is decreasing at the rate of 4

wel

Let's begin by listing out the information given to us:

8 am

airplane #1: x = 80870 ft, v = -450 ft/ min

airplane #2: x = 5000 ft, v = 900ft/min

We must note that the airplanes are moving at a constant speed. The equation for the airplanes is given by:

$\begin{gathered} E=x_1+vt----1 \\ E=x_2+vt----2 \\ where\colon E=elevation,ft;x=InitialElevation,ft; \\ v=velocity,ft\text{/}min;t=time,min \\ x_1=80,870ft,v=-450ft\text{/}min \\ E=80870-450t----1 \\ x_2=5,000ft,v=900ft\text{/}min \\ E=5000+900t----2 \end{gathered}$

We equate equations 1 & 2 to get the time both airlanes will be at the same elevation. We have:

$\begin{gathered} 5000+900t=80870-450t \\ \text{Add 450t to both sides, we have:} \\ 900t+450t+5000=80870-450t+450t \\ 1350t+5000=80870 \\ \text{Subtract 5000 from both sides, we have:} \\ 1350t+5000-5000=80870-5000 \\ 1350t=75870 \\ \text{Divide both sides by 1350, we have:} \\ \frac{1350t}{1350}=\frac{75870}{1350} \\ t=56.2min \\ \\ \text{After }56.2\text{ minutes, both airplanes will be at the same elevation} \end{gathered}$

The elevation at that time (when the elevations of the two airplanes are the same) is given by substituting the value of time into equations 1 & 2. We have:

$\begin{gathered} E_1=80870-450t \\ E_1=80870-450(56.2) \\ E_1=80870-25290 \\ E_1=55580ft \\ \\ E_2=5000+900t \\ E_2=5000+900(56.2) \\ E_2=5000+50580 \\ E_2=55580ft \\ \\ \therefore E_1\equiv E_2=55580ft \end{gathered}$

6 0

8 months ago

What is the solution to 0.25t = 0.25 - t ?

Ede4ka [16]

i think it's t=0.2 Hope it helps:)

8 0

2 years ago

Kalpana is rescuing a hiker. On Kalpana's GPS tracker, positive numbers represent the elevations of hikers above her, and negati

Margaret [11]

Answer:

the correct answer is A, (The hiker is 371 m below Kalpana.)

8 0