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kap26 [50]
3 years ago
6

WILL CROWN BRAINLIEST!!!

Mathematics
2 answers:
Anton [14]3 years ago
4 0
When x = 1 y =7
x=2     y=9
x=3     y=11
x=4     y=13
Mars2501 [29]3 years ago
3 0
Ready to be crowned. 

Plug in the x values. 

y=2x+5

y= 2(1)+5

y=2+5

y=7 

First point: (1,7)

Second one:
y=2(2)+5
y=4+5
y=9 

Second point: (2,9)

Third one:
y= 2(3)+5
y=6+5
y=11

Third point: (3,11)

Fourth one:
y=2(4)+5
y=8+5
y=13

Fourth point: (4,13)

The points are (in ordered pairs)

(1,7) (2,9) (3,11) (4,13)

I hope this helps!
~kaikers
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Natasha2012 [34]
If you had four rows you would have to put them in 4 groups of 12. 12 * 4=48.
50-48= 2. there will be 2 tiles left over
5 0
3 years ago
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How much greater than a whole is...
frosja888 [35]

Answer:

For A, 3/7 greater than a whole

For B, 1/5 greater than a whole

For C, 1/3 greater than a whole

Step-by-step explanation:

Subtract the number on the left from the number on the right. then put what you get over the number on the right

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Can you answer these for me please?? and re-think your answer
AVprozaik [17]

Answer:

A

Step-by-step explanation:

2(5)+5>13 then it becomes 15>13 so it is true u should do the rest and they become false so a is the answer

7 0
2 years ago
Give the general form of the equation of the line through (1,2) and is perpendicular to the line passing through (-6,-3)(6,3)
olga nikolaevna [1]

Answer:

4x+3y-10=0

Step-by-step explanation:

first find the gradient of the line that is perpendicular to the line of interest.

y2-y1/x2-x1

3--3/6--6

=3+3/6+6

=9/12

3/4

The gradient of the line of interest is the negative reciprocal of 3/4. Therefore m is -4/3

next, substitute information into

y-y1=m(x-x1)

y-2=-4/3 (x-1)

multiply both sides of equation by 3

3y-6=-4 (x-1)

expand brackets

3y-6=-4x+4

rearrange in general form

4x+3y-10=0

6 0
3 years ago
Find the length of a rectangle with a diagonal of 10 and a height of 8.
Dmitry_Shevchenko [17]

Answer:

The length of the rectangle is 6.

Step-by-step explanation:

Given: The diagonal of a rectangle is 10 and the height is 8.

Please understand, that a diagonal, divides the rectangle into two tringles.

To find the length of the rectangle, you can use Pythagoras on one of the right sided triangles, because the length of the triangle, is also the length of the rectangle!

<em>EXTRA:</em>

<em>If</em><em> you know the special 3 4 5 triangle, a so called Pythagorean Triple, then you can "see" the simularity between the numbers.</em>

<em>Instead of 5, a diagonal of 10 is given (factor of 2 bigger).</em>

<em>Instead of 4, the height of 8 is given (factor of 2 bigger</em><em>)</em><em>.</em><em> </em><em>By scaling the Pythagorean Triple 3 4 5 by a factor of 2, you get the numbers 6 8 10. Could it be, that the number we need to find, is six?</em>

Try to verify, by calculating the missing number (which is the length of the rectangle we are looking for).

a² + b² = c²

a = length (and is unknown)

b = height = 8

c = hypothenusa/diagonal = 10

Substitute the numbers given:

a² + 8² = 10²

Subtract 8² left and right of the = sign.

a² +8² -8² = 10² - 8²

a² + 0 = 100 - 64

a² = 36

a = + - √36

a = + - 6

<em>EXTRA</em><em>:</em>

<em>You</em><em> can ignore the -√36 = -6 part of the solution, because a length of -6 has no meaning here.</em>

a = 6

So, the length of the triangle is 6 and thus, the length of the rectangle is also 6.

8 0
3 years ago
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