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icang [17]
3 years ago
8

Solve by additionmethod3x - 84 = 3​

Mathematics
1 answer:
galina1969 [7]3 years ago
6 0
3x-84=3
+84
3x=87
87/3
x=29
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I need help!!! Parallel lines p and q are cut by two non parallel lines m and n as shown in the figure the value of x is degrees
S_A_V [24]

Answer:

x = 78° , y = 115°

Step-by-step explanation:

The angle adjacent to x on the left side is corresponding to 102° , then

x = 180° - 102° = 78°

----------------------------------------

y and 115° are corresponding angles and congruent, then

y = 115°

8 0
3 years ago
Can someone please do this ill mark brainliest
Svet_ta [14]

Answer:

-60  im pretty sure this is it

                                 

8 0
3 years ago
Use the following diagram and information to answer the question.
Reika [66]

Answer:

  b)  Julie can use properties of congruent triangles to show that AB≅BC and BC≅CD. Then she can show BC≅AD because opposite sides of a parallelogram are congruent

Step-by-step explanation:

On the assumption that Julie must show all four sides to be congruent, the one remaining step after using the properties of congruent triangles is to show that side AD is congruent to the rest of the sides. Answer choice B describes that.

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IMO, Julie is finished after she shows∠A≅∠B and AB≅BC, because a parallelogram will be a square if adjacent sides are congruent (makes it a rhombus) and adjacent angles are congruent (makes it a rectangle). A rhombus that is a rectangle is a square.

8 0
3 years ago
4+2(x-2)=2(x-1)+2<br> which one<br> A. Infinitesolutions<br> B.x=0<br> C.x=3<br> D.x=-2<br> E.x=-3
fredd [130]

Answer:

B

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
A sector of a circle makes a 127° angle at its centre. If the arc of the sector has length 36 mm, find
Veseljchak [2.6K]

Answer:

Approximately 68.5\; \rm mm.

Step-by-step explanation:

Convert the angle of this sector to radians:

\begin{aligned}\theta &= 127^{\circ} \\ &= 127^{\circ} \times \frac{2\pi}{360^{\circ}} \\ &\approx 2.22\end{aligned}.

The formula s = r\, \theta relates the arc length s of a sector of angle \theta (in radians) to the radius r of this sector.

In this question, it is given that the arc length of this sector is s = 36\; \rm mm. It was found that \theta = 2.22 radians. Rearrange the equation s = r\, \theta to find the radius r of this sector:

\begin{aligned} r&= \frac{s}{\theta} \\ &\approx \frac{36\; \rm mm}{2.22} \\ &\approx 16.2\; \rm mm\end{aligned}.

The perimeter of this sector would be:

\begin{aligned}& 2\, r + s \\ =\; & 2 \times 16.2\; {\rm mm} + 36\; {\rm mm} \\ =\; & 68.5\; \rm mm\end{aligned}.

8 0
3 years ago
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